var numbers = [3, 5, 7, 2];
var sum = numbers.reduce((x, y) => x + y);
console.log(sum); // returns 17
// other way
x = sumAll(1, 123, 500, 115, 44, 88);
function sumAll() {
var i;
var sum = 0;
for (i = 0; i < arguments.length; i++) {
sum += arguments[i];
}
return sum;
}