PYTHON

join two dictionaries python

z = {**x, **y}

python merge dictionaries

# Python >= 3.5:
def merge_dictionaries(a, b):
   return {**a, **b}
  
# else:
def merge_dictionaries(a, b):
    c = a.copy()   # make a copy of a 
    c.update(b)    # modify keys and values of a with the b ones
    return c

a = { 'x': 1, 'y': 2}
b = { 'y': 3, 'z': 4}
print(merge_dictionaries(a, b)) 		# {'y': 3, 'x': 1, 'z': 4}

python merge dictionaries

dict1 = {'color': 'blue', 'shape': 'square'}
dict2 = {'color': 'red', 'edges': 4}

dict1.update(dict2) #if a key exists in both, it takes the value of the second dict
# dict1 = {'color': 'red', 'shape': 'square', 'edges': 4}
# dict2 is left unchanged

python join dict

dict.update([other])

python join dict

def mergeDict(dict1, dict2):
   ''' Merge dictionaries and keep values of common keys in list'''
   dict3 = {**dict1, **dict2}
   for key, value in dict3.items():
       if key in dict1 and key in dict2:
               dict3[key] = [value , dict1[key]]
 
   return dict3
 
# Merge dictionaries and add values of common keys in a list
dict3 = mergeDict(dict1, dict2)
 
print('Dictionary 3 :')
print(dict3)

python merge dict

# Python 3.9+ is required
mergedDict = dict1 | dict2

python merge dictionaries

def merge_dicts(dict1, dict2):
        """Here's an example of a for-loop being used abusively."""
        return {**dict2, **{k: (v if not (k in dict2) else (v + dict2.get(k)) if isinstance(v, list) else merge_dicts(v, dict2.get(k))) if isinstance(v, dict) else v for k, v in dict1.items()}}