C

*= operator

“*=”: This operator is a combination of ‘*’ and ‘=’ operators. This operator 
first multiplies the current value of the variable on left to the value on the
right and then assigns the result to the variable on the left. 
(a *= b) can be written as (a = a * b)

If initially, the value stored in a is 5. Then (a *= 6) = 30.

->* operator

//we have a class
struct X
{
   void f() {}
   void g() {}
};

typedef void (X::*pointer)();
//ok, let's take a pointer and assign f to it.
pointer somePointer = &X::f;
//now I want to call somePointer. But for that, I need an object
X x;
//now I call the member function on x like this
(x.*somePointer)(); //will call x.f()
//now, suppose x is not an object but a pointer to object
X* px = new X;
//I want to call the memfun pointer on px. I use ->*
(px ->* somePointer)(); //will call px->f();

*= operator

“*=”: This operator is a combination of ‘*’ and ‘=’ operators. This operator 
first multiplies the current value of the variable on left to the value on the
right and then assigns the result to the variable on the left. 
(a *= b) can be written as (a = a * b)

If initially, the value stored in a is 5. Then (a *= 6) = 30.

->* operator

//we have a class
struct X
{
   void f() {}
   void g() {}
};

typedef void (X::*pointer)();
//ok, let's take a pointer and assign f to it.
pointer somePointer = &X::f;
//now I want to call somePointer. But for that, I need an object
X x;
//now I call the member function on x like this
(x.*somePointer)(); //will call x.f()
//now, suppose x is not an object but a pointer to object
X* px = new X;
//I want to call the memfun pointer on px. I use ->*
(px ->* somePointer)(); //will call px->f();