CSHARP

compare two binary tree

public bool IsEqual(Node first, Node second)
{
    if (first == null && second == null) return true;

    if(first != null && second != null)
    {
      return first.data == second.data && 
          IsEqual(first.rightChild,second.rightChild) &&
          IsEqual(first.leftChild,second.leftChild);
    }
    return false;
}


// Node structure

public class Node
{
    private int data;
    private Node leftChild;
    private Node rightChild;
    public Node(int data)
    {
      	this.data = data;
    }
}

compare binary trees

compare(tree1 ,tree2 ){

let x =tree1.count()
let y =tree2.count()

if(x==y)return true; else return false;
}


//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)