import java.util.*;
public class array
{
static Scanner sc=new Scanner(System.in);
public static void main(String[] args)
{
System.out.println("Enter the number of elements in the array:");
int x=sc.nextInt();
int arr[]=new int[x];
System.out.println("Enter the sorted elements in the array:");
for(int i=0; i<arr.length; i++)
{
arr[i]=sc.nextInt();
}
System.out.println("Enter the element to be searched for in the array:");
int y=sc.nextInt();
int max=arr.length-1;
int min=0;
int mid;
while(max>=min)
{
mid=(min+max)/2;
if(y==arr[mid])
{
System.out.println("The requested element is at index "+mid);
break;
}
else if(y>arr[mid])
min=mid+1;
else if(y<arr[mid])
max=mid-1;
if(min>max)
System.out.println("Requested element is not in the array.");
}
}
}
/*
Java Implementation of Binary Search Algorithm.
- Assuming the Array is Sorted (Ascending Order)
- returns the Index, if Element found.
- -1, if not found.
*/
public class BinarySearch {
int binarysearch(int[] array, int element) {
int a_pointer = 0;
int b_pointer = array.length -1;
if (array[a_pointer] == element) return a_pointer;
if (array[b_pointer] == element) return b_pointer;
while(a_pointer <= b_pointer){
int midpoint = a_pointer + (b_pointer - a_pointer) / 2;
if (array[midpoint] == element) return midpoint;
// ignoring the left half, if this is True.
if (array[midpoint] < element) a_pointer = midpoint + 1;
// ignoring the right half, if this is True.
else if (array[midpoint] > element) b_pointer = midpoint - 1;
}
return -1; // Element not Found
}
public static void main(String[] args) {
int[] list = {1, 2, 3, 4, 7, 9, 11, 12, 15, 19, 23, 36, 54, 87};
System.out.println(binarysearch(list, 19));
}
}
import java.util.*;
public class Search {
static int indexOfItem(List<String> list, String target) {
int first = 0;
int last = list.size() - 1;
while (first <= last) {
int midpoint = (first + last) / 2;
int comparisonResult = list.get(midpoint).compareTo(target);
if (comparisonResult == 0) {
return midpoint;
} else if (comparisonResult < 0) {
first = midpoint + 1;
} else {
last = midpoint - 1;
}
}
// We have to return an integer, so return an "impossible"
// index to indicate value was not found.
return -1;
}
public static void main(String[] args) {
// Note that the list is sorted this time!
ArrayList<String> list = new ArrayList<String>(
Arrays.asList("Elida Sleight", "Francina Vigneault", "Lucie Hansman", "Nancie Rubalcaba"));
System.out.println(indexOfItem(list, "Lucie Hansman"));
}
}
//
// Source code recreated from a .class file by IntelliJ IDEA
// (powered by FernFlower decompiler)
//
package com.SortingAlgorithm;
import java.util.Scanner;
public class BinarySearch {
public BinarySearch() {
}
// write a function that performs your binary search.
static int binarySearch(int[] arr, int target, int n) {
// declare your right and left pointers.
int lp = 0;
int rp = n - 1;
// write loop that compares the left & right pointers and returns the mid point
while(lp <= rp) {
int mid = (lp + rp) / 2;
if (target == arr[mid]) {
return mid;
}
// write an if statement to check for target element at mid point
if (target < arr[mid]) {
rp = mid - 1;
} else {
lp = mid + 1;
}
}
return -1;
}
// driver method to test the above
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int target = false;
System.out.print("Enter the number of elements tou on the array list! :");
int n = scanner.nextInt();
int[] arr = new int[n];
System.out.println("enter " + n + " Elements");
for(int i = 0; i < n; ++i) {
arr[i] = scanner.nextInt();
}
System.out.println("Enter target value: ");
int target = scanner.nextInt();
int index = binarySearch(arr, target, n);
if (index != -1) {
System.out.println("Element is at index: " + index);
} else {
System.out.format("Element not found");
}
}
}
// Java Binary Search Algorithm
// ----------------------------
/*
Time Complexity
Best Time Complexity:O(1)
Average Time Complexity:O(log n)
Worst Time Complexity:O(log n)
Space Complexity
No auxiliary space is required in Linear Search implementation.
Hence space complexity is:O(1)
*/
public class BinarySearch {
// Searching using Recursive approach
public static int Search(int arr[], int value, int start, int end) {
int center = (start + end) / 2;
if (start <= end) {
if (value == center) {
return center;
}
if (value < center) {
return Search(arr, value, start, center - 1);
}
if (value > center) {
return Search(arr, value, center + 1, end);
}
}
return -1;
}
public static void main(String[] args) {
int arr[] = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
int Index = Search(arr, 9, 0, arr.length);
if (Index == -1) {
System.out.println("Value Not Found");
} else {
System.out.println("Value found at Index: " + Index);
}
}
}
// Java implementation of recursive Binary Search
class BinarySearch {
// Returns index of x if it is present in arr[l..
// r], else return -1
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r - l) / 2;
// If the element is present at the
// middle itself
if (arr[mid] == x)
return mid;
// If element is smaller than mid, then
// it can only be present in left subarray
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
// Else the element can only be present
// in right subarray
return binarySearch(arr, mid + 1, r, x);
}
// We reach here when element is not present
// in array
return -1;
}
// Driver method to test above
public static void main(String args[])
{
BinarySearch ob = new BinarySearch();
int arr[] = { 2, 3, 4, 10, 40 };
int n = arr.length;
int x = 10;
int result = ob.binarySearch(arr, 0, n - 1, x);
if (result == -1)
System.out.println("Element not present");
else
System.out.println("Element found at index "
+ result);
}
}
/* This code is contributed by Rajat Mishra */
package com.community.java;
/**
*
* @author Akira
*/
public class ContohBinarySearch {
private final int [] data = {5, 9, 12, 15, 17, 23, 27, 38, 42, 54, 64, 78, 90};
private void tampilData(){
for (int i : data) {
System.out.print(i+" ");
}
System.out.println();
}
public String pencarianBinary(int key) {
int bawah = 0;
int atas = data.length - 1;
while (atas >= bawah) {
int tengah = (bawah + atas) / 2;
if (key < data[tengah]){
atas = tengah - 1;
} else if (key == data[tengah]){
return "Nomor "+key+" Berada Pada Urutan Ke - "+(tengah+1);
}else{
bawah = tengah + 1;
}
}
return "Data Tidak Ditemukan";
}
public static void main(String args []){
ContohBinarySearch obj = new ContohBinarySearch();
obj.tampilData();
System.out.println(obj.pencarianBinary(8));
}
}
public class Main{ public static void binarySearch(int arr[], int a, int b, int key){ int mid = (a + b)/2; while( a <= b ){ if ( arr[mid] < key ){ a = mid + 1; }else if ( arr[mid] == key ){ System.out.println("number is here " + mid); break; }else{ b = mid - 1; } mid = (a + b)/2; } if ( a > b ){ System.out.println("number not here"); } } public static void main(String args[]){ int arr[] = {10,20,30,40,50}; int key = 30; int b=arr.length-1; binarySearch(arr,0,b,key); } }