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how to check if number is even

if ( n % 2 == 0 ) {
	// n is even
}
else {
	//otherwise odd
}

check if a number is even or odd

// @Author: Subodh 
// 1 liner solution
(num & 1) ? cout << num << " is odd" : cout << num << " is even" << endl;

Even or odd number

/* Program to check whether the input integer number 
 * is even or odd using the modulus operator (%)
 */
#include<stdio.h>
int main()
{
   // This variable is to store the input number 
   int num;
 
   printf("Enter an integer: ");
   scanf("%d",&num);
 
   // Modulus (%) returns remainder
   if ( num%2 == 0 )
      printf("%d is an even number", num);
   else
      printf("%d is an odd number", num);
 
   return 0;
}

check whether number is even or odd

#check wheather a is odd or even
'''interactive mode
>>> 10%2
0....................False #(False==0)
>>> 5%2
1....................True  #(True==1)'''
#scriptive mode
a=int(input('enter:'))
if a%2:
    print("its odd")#solution gives true if 'a' value is even
else:
    print("its even")#solution gives false if 'a' value is odd 
print('hope it helped')
#output
#False
enter:100
its even
hope it helped
#even
enter:101
its odd
hope it helped

Finding Even and Odd Numbers

<?php
      $check1 = 3534656;
      $check2 = 3254577;
      if($check1%2 == 0) {
        echo "$check1 is Even number <br/>";
        
      } else {
        echo "$check1 is Odd number <br/>";
      }

      if($check2%2 == 0) {
        echo "$check2 is Even number";
      } else {
        echo "$check2 is Odd number";
      }
    ?>

check a number is odd or even

def is_even(num):
	return not bool(num % 2)