JAVASCRIPT

finding second highest number in array

public static int secHigh(int arr[]){
  int firstHigh = 0,secHigh = 0;
  for(int x: arr){
    if(x > firstHigh){
      secHigh = firstHigh;
      firstHigh = x;
    }else if(x > secHigh){
      secHigh = x;
    }
  }
  return secHigh;
}

find second smallest number in array

const array = [32, 22, 53, 92, 20, 34, 23, 11, 17];
let smallestNum = array[0];
let secondSmallestNum = 0;
for (let i = 1; i < array.length; i++) {
  if (array[i] < smallestNum) {
    secondSmallestNum = smallestNum;
    smallestNum = array[i];
  } else if (array[i] !== smallestNum && array[i] < secondSmallestNum) {
    secondSmallestNum = array[i];
  }
}
console.log(smallestNum);
console.log(secondSmallestNum);

Find second largest number in an array

// Java program to find second largest
// element in an array
import java.util.*;
class GFG{
 
// Function to print the
// second largest elements
static void print2largest(int arr[],
                          int arr_size)
{
  int i, first, second;
 
  // There should be
  // atleast two elements
  if (arr_size < 2)
  {
    System.out.printf(" Invalid Input ");
    return;
  }
 
  // Sort the array
  Arrays.sort(arr);
 
  // Start from second last element
  // as the largest element is at last
  for (i = arr_size - 2; i >= 0; i--)
  {
    // If the element is not
    // equal to largest element
    if (arr[i] != arr[arr_size - 1])
    {
      System.out.printf("The second largest " +
                        "element is %d
", arr[i]);
      return;
    }
  }
 
  System.out.printf("There is no second " +
                    "largest element
");
}
 
// Driver code
public static void main(String[] args)
{
  int arr[] = {12, 35, 1, 10, 34, 1};
  int n = arr.length;
  print2largest(arr, n);
}
}
 
// This code is contributed by gauravrajput1