JAVASCRIPT

array sum javascript

const arr = [1, 2, 3, 4];
const sum = arr.reduce((a, b) => a + b, 0);
// sum = 10

how to sum array elements in javascript

// codewars solution
// leetcode solution
// and more

function sum(arr) {
  return arr.reduce( (x,y) => x+y, 0);
}

sum([1, 2, 3, 4]);
// 10
sum([2, 4, 1, 3, 5]);
// 15

// enjoy :)

sum an array in javascript

const arr = [1,2,3,4,5]
const sum = arr.reduce((a,b) => a+b)

sum of all numbers in an array javascript

const arrSum = arr => arr.reduce((a,b) => a + b, 0)

js sum of array

[1, 2, 3, 4].reduce((a, b) => a + b, 0)

// Output: 10

javascript sum of array

const sum = arr => arr.reduce((a, b) => a + b, 0);

sum of array elements in javascript

let arr = [2, 4, 1, 3, 5];
let result = 0;

for (let i = 0; i < arr.length; i++) {
   result += arr[i];
}

console.log(result); // 15

sum of numbers in array with javascript

const sumNums = (arr)=>{
    let sum=0;
    for (let t = 0; t < arr.length; t++) {
        if(typeof arr[t] == "number" ){

           sum = sum + arr[t] ;
        }
        
    }
    return sum;
}

//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)

js sum of int in array

const sum = [1, 2, 3].reduce((partialSum, a) => partialSum + a, 0);
console.log(sum); // 6

Array sum by function in javascript

function sumNumbers(numbers) {
    var sum = 0;
    for (let i = 0; i < numbers.length; i++) {
        var elements = numbers[i];
        sum = sum + elements;
    }
    return sum;
}
const numbers = [2, 3, 4, 5, 2, 4];
console.log(sumNumbers(numbers));
//Output: 20

sum values in array javascript

const num = [1, 3, 1, 1] 
const reducer = (accumulator, currentValue) => accumulator + currentValue;
const sum = num.reduce(reducer);
console.log(sum)
// (1+3+1+1) = 6

how to get sum array in javascript

let sum1 = (arr) => arr.reduce( (x,y) => x+y);

console.log(sum1([2, 4, 9]));
console.log(sum1([15, 200, 18, 0, 18, 18]));
console.log(sum1([100, 4, 17, 29, 81]));

how to find the sum of array using JavaScript

// If you do not want to use array.reduece you can itereate through the array and then get the solution.
const  getSum = (arr)=>{
  let sum = 0;
  for(key of arr){
    sum += key
  }
  return sum
}

js sum

const array = [1, 2, 3];
const result = array.reduce((accumulator, current) => accumulator + current, 0);
// result === 1 + 2 + 3;

js array elements sum

[1, 2, 3, 4].reduce((a, b) => a + b, 0)

sum array elements in javascript

console.log(
  [1,2,3].reduce(function(acc, val) { return acc + val; })
)

console.log(
  [].reduce(function(acc, val) { return acc + val; }, 0)
)
 Run code snippetHide results

sum of array javascript

const arr = [1,2,3]
const sumOfArr = arr.reduce((a,b) => {
  return a + b
})

sum array elements in javascript

console.log(
  [1,2,3].reduce(function(acc, val) { return acc + val; })
)

console.log(
  [].reduce(function(acc, val) { return acc + val; }, 0)
)
 Run code snippetHide results

how to sum the array values in javascript

[1, 2, 3, 4].reduce((pre,curr)=>pre+curr,0)

sum of an array

const sum = (...args) => args.reduce((a, b) => a + b, 0);
console.log(sum(1,2,3)); // returns 6

sum array elements in javascript

console.log(
  [1,2,3].reduce(function(acc, val) { return acc + val; })
)

console.log(
  [].reduce(function(acc, val) { return acc + val; }, 0)
)
 Run code snippetHide results

sum function in javascript

let sum = (...para) => para.reduce((d,b) => d + b);

sum array elements in javascript

console.log(
  [1,2,3].reduce(function(acc, val) { return acc + val; })
)

console.log(
  [].reduce(function(acc, val) { return acc + val; }, 0)
)
 Run code snippetHide results

sum array elements in javascript

console.log(
  [1,2,3].reduce(function(acc, val) { return acc + val; })
)

console.log(
  [].reduce(function(acc, val) { return acc + val; }, 0)
)
 Run code snippetHide results

sum of array

int sumofarr(int *a, int n) {
	if (n>1)
        return a[n-1]+sumofarr(a, n-1);
    return a[0];
}