var colors = ["red","blue","car","green"];
var carIndex = colors.indexOf("car");//get "car" index
//remove car from the colors array
colors.splice(carIndex, 1); // colors = ["red","blue","green"]
array.splice(indexToStartFrom, numbersOfItemsToBeDeleted);
// for deleting only one element
array.splice(index, 1);
//index = index of element in an array;
how to delete an element of an array in javascript
//you can use two functions depending of what you want to do:
let animals1 = ["dog", "cat", "mouse"]
delete animals1[1]
/*this deletes all the information inside "cat" but the element still exists
so now you'll have this:*/
console.log(animals1)//animals1 = ["dog", undefined, "mouse"]
//if you want to delete it completely, you have to use array.splice:
let animals2 = ["dog", "cat", "mouse"]
animals2.splice(1, 1)
/*the first number means the position from which you want to start to delete
and the second is how much elements will be deleted*/
console.log(animals2)//animals2 = ["dog", "mouse"]
/*Now you don't have undefined
If you did this:*/
let animals3 = ["dog", "cat", "mouse"]
animals3.splice(0, 2)//you'll have this:
console.log(animals3)//animals 3 = "mouse"
/*This happens because I put a 2 in the second parameter so it deleted
two elements from position 0
Try copying this code in your console and whatch*/
var colors = ["red", "orange", "yellow", "green"];
colors = colors.splice(3, 1); // Starts removing from the third element, and deletes 1 element
// Array.splice(startingElement, elementYouWantToRemove);
// Create a function to do it easily and how many time you want!
const deleteFromArray = (array, value) => {
let newArray = array.filter(item => item !== value)
return newArray;
}
var array = [1, 2, 3, 4]
const newArr = deleteFromArray(array, 2)
console.log('Changed array:', newArr);
// Changed array: [ 1, 3, 4 ]
//Warning !
//Array elements can be deleted using the JavaScript operator delete.
//Using delete leaves undefined holes in the array.
//Use pop() or shift() instead
const fruits = ["Banana", "Orange", "Apple", "Mango"];
delete fruits[0];Warning !
// >> ["undefined", "Orange", "Apple", "Mango"];
//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)
let dailyActivities = ['work', 'eat', 'sleep', 'exercise'];
// remove the last element
dailyActivities.pop();
console.log(dailyActivities); // ['work', 'eat', 'sleep']
// remove the last element from ['work', 'eat', 'sleep']
const removedElement = dailyActivities.pop();
//get removed element
console.log(removedElement); // 'sleep'
console.log(dailyActivities); // ['work', 'eat']
/*
* C program to delete an element from array at specified position
*/
#include <stdio.h>
#define MAX_SIZE 100
//this code does not literally delete an element
//this does rewrite the rest of the array over the element to be deleted
//and reduceing the count by one
//https://codeforwin.org/2015/07/c-program-to-delete-element-from-array.html
int main()
{
int arr[MAX_SIZE];
int i, size, pos;
/* Input size and element in array */
printf("Enter size of the array : ");
scanf("%d", &size);
printf("Enter elements in array : ");
for(i=0; i<size; i++)
{
scanf("%d", &arr[i]);
}
/* Input element position to delete */
printf("Enter the element position to delete : ");
scanf("%d", &pos);
/* Invalid delete position */
if(pos < 0 || pos > size)
{
printf("Invalid position! Please enter position between 1 to %d", size);
}
else
{
/* Copy next element value to current element */
for(i=pos-1; i<size-1; i++)
{
arr[i] = arr[i + 1];
}
/* Decrement array size by 1 */
size--;
/* Print array after deletion */
printf("
Elements of array after delete are : ");
for(i=0; i<size; i++)
{
printf("%d ", arr[i]);
}
}
return 0;
}