var numbers = [3, 5, 7, 2];
var sum = numbers.reduce((x, y) => x + y);
console.log(sum); // returns 17
// other way
x = sumAll(1, 123, 500, 115, 44, 88);
function sumAll() {
var i;
var sum = 0;
for (i = 0; i < arguments.length; i++) {
sum += arguments[i];
}
return sum;
}
const sumNums = (arr)=>{
let sum=0;
for (let t = 0; t < arr.length; t++) {
if(typeof arr[t] == "number" ){
sum = sum + arr[t] ;
}
}
return sum;
}
//if you find this answer is useful ,
//upvote ⇑⇑ , so can the others benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)
// If you do not want to use array.reduece you can itereate through the array and then get the solution.
const getSum = (arr)=>{
let sum = 0;
for(key of arr){
sum += key
}
return sum
}
// define a list
const list = [1,2,3,4,5];
// create a function return result of sum of elements
const result = () => {
let sum = 0;
for (let i = 0; i < list.length; i++) {
sum += list[i];
}
return sum
}
console.log(result());
// sum of all number
function sum(){
let InValue =0
for (let index = 0; index < arguments.length; index++) {
InValue +=arguments[index];
}
console.log(`Total sum of all number is = ${InValue} `);
}
sum(10,10,10);