var timestamp = new Date().getTime();
const ts = () => Math.floor(new Date().getTime() / 1000);
var timestamp = new Date().getTime();
console.log(timestamp);
var currentTimeInSeconds=Math.floor(Date.now()/1000); //unix timestamp in seconds
var currentTimeInMilliseconds=Date.now(); // unix timestamp in milliseconds
const currentTimeInMilliseconds=Date.now(); // unix timestamp in milliseconds
var tempsEnMs = Date.now();
//Date, Time, Timestamp
var today = new Date();
var DD = String(today.getDate()).padStart(2, '0');
var MM = String(today.getMonth() + 1).padStart(2, '0'); //January is 0!
var YYYY = today.getFullYear();
var hh = today.getHours();
var mm = today.getMinutes();
var ss = today.getSeconds();
today = YYYY + MM + DD + hh + mm + ss;
console.log('Date-Time: ', today);
let date1 = "15/03/2020";
let date2 = "15:03"
//to timestamp
var date = date1.split("/")
date= date[2] + "-" + date[1] + "-" + date[0]
date = new Date(date + "T" + date2 + ":00")
console.log(date.getTime())
//to String
date = date.toLocaleString()
console.log(date)
const currentTimeInSeconds=Math.floor(Date.now()/1000); //unix timestamp in seconds
+ new Date()
if (!Date.now) {
Date.now = function() { return new Date().getTime(); }
}
var myDate = new Date("Jul 21, 2013");
var date = myDate.getDate();
var month = myDate.getMonth();
var year = myDate.getFullYear();
function pad(n) {
return n<10 ? '0'+n : n
}
var ddmmyyyy = pad(date) + "-" + pad(month + 1) + "-" + year;
Short & Snazzy:
+ new Date()
A unary operator like plus triggers the valueOf method in the Date object and it returns the timestamp (without any alteration).