Php

UPDATE
    table_name
SET
    column_name = REPLACE(column_name, 'text to find', 'text to replace with')
WHERE
    column_name LIKE '%text to find%';

PREVIOUS	NEXT

Code Example
Php :: php timezone asia dhaka
Php :: php max input vars wordpress wp-config
Php :: php content type xml
Php :: php cut off first x characters
Php :: select distinct laravel
Php :: laravel foreach loop index
Php :: php get subdomain
Php :: php find multiple strings in string
Php :: wordpress enqueue style child theme
Php :: woocommerce buy product skip cart
Php :: laravel publish email template
Php :: how assign current date to input type date html in php
Php :: php difference between two dates in years months and days
Php :: string to datetime php
Php :: php mysql count rows
Php :: importing current year in laravel blade
Php :: php delete array item by value not key
Php :: base64 decode in php
Php :: time to load php page
Php :: wp max revisions
Php :: php get id from url
Php :: composer create project laravel 7
Php :: display errors in codeigniter
Php :: - root composer.json requires php ^7.1.3 but your php version (8.0.3) does not satisfy that requirement.
Php :: php check if session is running
Php :: carbon date from format
Php :: preg_replace remove double quotes
Php :: php to save txt html
Php :: how to get length of object in php
Php :: str_includes php