PYTHON

python palindrome string

s = "001100"

if s == s[::-1]:
    print("palindrome string")
else:
    print("Not a palindrome string.")

python palindrome

def palindrome(a):
    return a == a[::-1]

palindrome('radar') 		# True

Palindrome Check using for loop in python

p = list(input())
for i in range(len(p)):
    if p[i] == p[len(p)-1-i]:
        continue
    else:
         print("NOT PALINDROME")
         break
else:
    print("PALINDROME")

How to check for palindromes in python

def is_palindrome(s):
  reverse = s[::-1]
  if (s == reverse):
    return True
  return False

s1 = 'racecar'
s2 = 'hippopotamus'

print(''racecar' a palindrome -> {}'.format(is_palindrome(s1)))
print(''hippopotamus' a palindrome -> {}'.format(is_palindrome(s2)))


# output

# 'racecar' is a palindrome -> True
# 'hippopotamus' is a palindrome -> False

palindrome string python

a=input('enter a string :')# palindrome in string
b=a[::-1]
if a==b:
    
 print(a,'is a palindrome')
else:
 print(a,'is not a palindrome')
 print('a is not equal to b')
 if a!=b:
   print(b, 'the reverse of', a)
#output:
--------------------------------------------------------------------------------
case-I
# not palindrome
enter a string :1254
1254 is not a palindrome
a is not equal to b
4521 the reverse of 1254
--------------------------------------------------------------------------------
case-II
# palindrme
enter a string :12321
12321 is a palindrome

palindrome of a number in python

num=int(input("Enter a no.:"))
rev=0
num1=num
while num!=0:
    rev=rev*10+(num%10)
    num=num//10
if num1==rev:
    print(num1," is a palindrome")
else:
    print(num1," is not a palindrome") 

Python - How To Check if a String Is a Palindrome

word = input() if str(word) == str(word)[::-1] :     print("Palindrome") else:     print("Not Palindrome")

python palindrome program

n = input("Enter the word and see if it is palindrome: ") #check palindrome
if n == n[::-1]:
    print("This word is palindrome")
else:
    print("This word is not palindrome")
    print("franco")

Python Program to Check if binary representation is a palindrome

# Function to check if binary representation of
# a number is palindrome or not
 
def binarypalindrome(num):
 
     # convert number into binary
     binary = bin(num)
 
     # skip first two characters of string
     # because bin function appends '0b' as
     # prefix in binary representation of
     # a number
     binary = binary[2:]
 
     # now reverse binary string and compare
     # it with original
     return binary == binary[-1::-1]
 
# Driver program
if __name__ == "__main__":
    num = 9
    print binarypalindrome(num)

How to check if a given string is a palindrome, in Python?

"""
This implementation checks whether a given
string is a palindrome. A string is 
considered to be a palindrome if it reads the
same forward and backward. For example, "kayak"
is a palindrome, while, "door" is not. 

Let n be the length of the string

Time complexity: O(n), 
Space complexity: O(1)
"""
def isPalindrome(string):
    # Maintain left and right pointers
    leftIdx = 0
    rightIdx = len(string)-1
    while leftIdx < rightIdx:
        # If chars on either end don't match
        # string cannot be a palindrome
        if string[leftIdx] != string[rightIdx]:
            return False
        # Otherwise, proceed to next chars
        leftIdx += 1
        rightIdx -= 1
    return True

print(isPalindrome("kayak"))  # True
print(isPalindrome("door"))  # False

python palindrome

def isPalindrome(s):
    return s == s[::-1]
 
 
# Driver code
s = "malayalam"
ans = isPalindrome(s)
 
if ans:
    print("Yes")
else:
    print("No")

how to check a string is palindrome or not in python

s = "001100"

if s == s[::-1]:
    print(s, "is a Palindrome string.")
else:
    print("Not a palindrome string.")

    

How to check palindrom in python

myString = "aba"
if myString == myString[::-1]:
	print("The string '" + myString + "' is a palindrome")
else:
	print("The string '" + myString + "' is not a palindrome")

check palindrome in python

string = input("Type a string: ")
if string[::-1] == string: 
	print(string,"This string is Palindrome")
else:
	print(string,"This string is not Palindrome")

palindrome checker python

value = input("Enter a Word: ")

if value == value[::-1] :
    print(value)
    print(value[::-1])
    print("THIS WORD IS A PALINDROME")
else :
    print(value)
    print(value[::-1])
    print("THIS WORD IS NOT A PALINDROME")

how to print palindrome number from 1 to n in python

n = int(input())
if n < 100:
    for i in range(1, n+1):
        s = str(i)
        if s == s[::-1]:
            print(i)

python palindrome check

#Palindrome check
word = 'reviver'
p = bool(word.find(word[::-1]) + 1)
print(p) # True

palindrome words python

mes=input("Enter the word and see if it is palindrome ")
if mes==mes[::-1]:
    print("This word is palindrome")
else:
    print("This word is not palindrome")

finding palindrome in python

is_palindrome = lambda phrase: phrase == phrase[::-1]

print(is_palindrome('anna')) # True 
print(is_palindrome('rats live on no evil star')) # True 
print(is_palindrome('kdljfasjf')) # False 

palindrome of a number in python

# Python3 code to demonstrate
# checking a number is palindrome
# using str() + string slicing
  
# initializing number 
test_number = 9669669
  
# printing the original number 
print ("The original number is : " + str(test_number))
  
# using str() + string slicing
# for checking a number is palindrome
res = str(test_number) == str(test_number)[::-1]
  
# printing result
print ("Is the number palindrome ? : " + str(res))

palindrome of a number in python

# Python3 code to demonstrate
# checking a number is palindrome
# using math.log() + recursion + list comprehension
import math
   
# the recursive function to reverse
def rev(num):
    return int(num != 0) and ((num % 10) * 
             (10**int(math.log(num, 10))) + 
                          rev(num // 10))
  
# initializing number 
test_number = 9669669
  
# printing the original number 
print ("The original number is : " + str(test_number))
  
# using math.log() + recursion + list comprehension
# for checking a number is palindrome
res = test_number == rev(test_number)
  
# printing result
print ("Is the number palindrome ? : " + str(res))

function palindrome python

bilangan = (5 % 3 ** 2) + (3 + 2 * 2) * (4 - 2) 
print(bilangan)

palindrome program in python

# Recursive function to check if a
# string is palindrome
def isPalindrome(s):
 
    # to change it the string is similar case
    s = s.lower()
    # length of s
    l = len(s)
 
    # if length is less than 2
    if l < 2:
        return True
 
    # If s[0] and s[l-1] are equal
    elif s[0] == s[l - 1]:
 
        # Call is palindrome form substring(1,l-1)
        return isPalindrome(s[1: l - 1])
 
    else:
        return False
 
# Driver Code
s = "MalaYaLam"
ans = isPalindrome(s)
 
if ans:
    print("Yes")
 
else:
    print("No")

how to print palindrome number from 1 to n in python

n = int(input())
if n < 100:
    for i in range(1, n+1):
        strI = str(i)
        lStrI = list(strI)
        rList = list(reversed(lStrI))
        if lStrI == rList:
            print(i)

python palindrome fuction

def is_palindrome(input_string):
	# Create two strings, to compare them
	new_string = ""
	reverse_string = ""
	# Traverse through each letter of the input string
	for x in range(len(input_string)):
    # This will give x the value of all the possible index numbers for each iteration
		# Add any non-blank letters to the 
		# end of one string, and to the front
		# of the other string. 
		if input_string[x] != " ":
			new_string += input_string[x]
			reverse_string = new_string[::-1]
	# Compare the strings
	if new_string.lower() == reverse_string.lower():
		return True
	return False
    
print(is_palindrome("Never Odd or Even")) # Should be True

palindrome python

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string=input(("Enter a string:"))
if(string==string[::-1]):
      print("The string is a palindrome")
else:
      print("Not a palindrome")

python palindrome program

palindrome 

python palindrome

#palindrome