PYTHON

combination python

# 1. Print all combinations 
from itertools import combinations

comb = combinations([1, 1, 3], 2)
print(list(combinations([1, 2, 3], 2)))
# Output: [(1, 2), (1, 3), (2, 3)]

# 2. Counting combinations
from math import comb
print(comb(10,3))
#Output: 120

combinations python

from itertools import combinations

school_subjects = ["math", "science", "history", "geography", "language arts", "Spanish"]

num_per_combos = 3

combos = list(combinations(school_subjects, num_per_combos))

for lists in combos:
    for combo in lists:
        print(combo + " ")
    print("
")

how to get all possible combinations in python

all_combinations = [list(zip(each_permutation, list2)) for each_permutation in itertools.permutations(list1, len(list2))]

python possible combinations

import math
n=7
k=5
print(math.comb(n, k))

all possible combinations in python

import itertools

list1 = list(range(5, 10))
list2 = [1, 2, 3]
list = [list1, list2]

combination = [p for p in itertools.product(*list)]
print(combination)
PythonCopy

python combinations

import itertools
def subs(l):
    res = []
    for i in range(1, len(l) + 1):
        for combo in itertools.combinations(l, i):
            res.append(list(combo))
    return res

python compute all combinations

import itertools

stuff = [1, 2, 3]
for L in range(len(stuff) + 1):
    for subset in itertools.combinations(stuff, L):
        print(subset)

python combinations function

def combinations(iterable, r):
    pool = tuple(iterable)
    n = len(pool)
    for indices in permutations(range(n), r):
        if sorted(indices) == list(indices):
            yield tuple(pool[i] for i in indices)

Combination in python

from itertools import permutations
from itertools import combinations
p = permutations([1,2,4]) # or  permutations([1, 2, 3], 2)
for i in p:
    print(i)
c = combinations([1,2,3],2)
for j in c:
    print(j)