PYTHON
pandas dataframe from dict
data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
pd.DataFrame.from_dict(data)
convert a dictionary into dataframe python
import pandas as pd
data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
pd.DataFrame.from_dict(data, orient='index').T
pandas dataframe from dict
>>> data = {'row_1': [3, 2, 1, 0], 'row_2': ['a', 'b', 'c', 'd']}
>>> pd.DataFrame.from_dict(data, orient='index')
0 1 2 3
row_1 3 2 1 0
row_2 a b c d
pandas dataframe from dict
>>> data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
>>> pd.DataFrame.from_dict(data)
col_1 col_2
0 3 a
1 2 b
2 1 c
3 0 d
pandas dataframe from dict
>>> pd.DataFrame.from_dict(data, orient='index',
... columns=['A', 'B', 'C', 'D'])
A B C D
row_1 3 2 1 0
row_2 a b c d
convert dict to dataframe
#Lazy way to convert json dict to df
pd.DataFrame.from_dict(data, orient='index').T
build dataframe from dictionary
data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
>>> pd.DataFrame.from_dict(data)
col_1 col_2
0 3 a
1 2 b
2 1 c
3 0 d
dataframe from dict
pd.DataFrame.from_dict(data)
create pandas dataframe from dictionary
In [11]: pd.DataFrame(d.items()) # or list(d.items()) in python 3
Out[11]:
0 1
0 2012-07-02 392
1 2012-07-06 392
2 2012-06-29 391
3 2012-06-28 391
...
In [12]: pd.DataFrame(d.items(), columns=['Date', 'DateValue'])
Out[12]:
Date DateValue
0 2012-07-02 392
1 2012-07-06 392
2 2012-06-29 391
create a dataframe from dict
create a dataframe from dict (function)
import pandas as pd
def create_df():
data = {'col_1': [3, 2, 1, 0], 'col_2': ['a', 'b', 'c', 'd']}
return pd.DataFrame.from_dict(data)
create_df()
convert pandas dataframe to dict with a column as key
df.set_index('columnName').T.to_dict()
create a dictionary from dataframe
input->
a b
0 red 0.500
1 yellow 0.250
2 blue 0.125
dict(df.values)
output -> {'red': '0.500', 'yellow': '0.250', 'blue': '0.125'}
pandas dataframe from dict
# import pandas library
import pandas as pd
# dictionary
details = {
'Ankit' : 22,
'Golu' : 21,
'hacker' : 23
}
# creating a Dataframe object from a list
# of tuples of key, value pair
df = pd.DataFrame(list(details.items()))
df