Python

Search

pandas select row by index

#for single row
df.loc[ index , : ]

# for multiple rows
indices = [1, 20, 33, 47, 52 ]
new_df= df.iloc[indices, :]

Comment

dataframe select row by index value

In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))

In [2]: df
Out[2]: 
          A         B
0  1.068932 -0.794307
2 -0.470056  1.192211
4 -0.284561  0.756029
6  1.037563 -0.267820
8 -0.538478 -0.800654

In [5]: df.iloc[[2]]
Out[5]: 
          A         B
4 -0.284561  0.756029

In [6]: df.loc[[2]]
Out[6]: 
          A         B
2 -0.470056  1.192211

Comment

PREVIOUS	NEXT

Code Example
Python :: hexdigest python
Python :: take columns to rows in pandas
Python :: python basic programs
Python :: virtual environment python
Python :: programação funcional python - lambda
Python :: connect and disconnect event on socketio python
Python :: get_permissions
Python :: longest common prefix
Python :: global var in python
Python :: list insert python
Python :: elif python
Python :: euclidean distance
Python :: Math Module cos() Function in python
Python :: python any() function
Python :: how to store the variable in dictionary
Python :: Converting time python
Python :: convert sentence to list of words python
Python :: python online compiler
Python :: how to access pandas column
Python :: stack python
Python :: python import statement
Python :: TRY
Python :: python variables and data types
Python :: python -
Python :: add items to list python
Python :: why is c faster than python
Python :: dfs algorithm python
Python :: python get item from set
Python :: firestore search query flutter
Python :: crud python

Search

PYTHON

pandas select row by index

dataframe select row by index value

ADD CONTENT