Python

Search

discord pycord add a URL button in a subclassed view

class helpView(View):
  def __init__(self):
    super().__init__(timeout=None)

    supportServerButton = discord.ui.Button(label='Support Server', style=discord.ButtonStyle.gray, url='https://discord.com')
    self.add_item(supportServerButton)

  @discord.ui.button(label='Commands', style=discord.ButtonStyle.green)
  async def command_callback(self, button, interaction):
    await interaction.response.edit_message(embed=commandEmbed, view=commandView())

Comment

PREVIOUS	NEXT

Code Example
Python :: linear zoeken python
Python :: remove cooldown discord python
Python :: Kinesis Client get_records response json
Python :: python on_mouse_down/collidepoint
Python :: vscode how to extend output size in jupyter notebook
Python :: permcheck codility python
Python :: implementing a bubble sort in python
Python :: onetoone vs foreign key django
Python :: python union type
Python :: pyglet on close
Python :: the command
Python :: shared a local host django
Python :: how to print a text in python
Python :: read file python
Python :: django app directory
Python :: improt kmean
Python :: get size of square matrix python
Python :: numpy split to chunks of equal size
Python :: obspy stats
Python :: numpy np sign change in df pandas zero crossing
Python :: python geet second item in generator
Python :: paystack python
Python :: Freqtrade - Informative Pairs
Python :: assertRaises property
Python :: modbusfc03 python
Python :: next function with inherited list python
Python :: python text to speech arabic
Python :: rename a column
Python :: read file bytes python
Python :: how to create a window in pygame

Search

PYTHON

discord pycord add a URL button in a subclassed view

ADD CONTENT