Search
 
SCRIPT & CODE EXAMPLE
 

PYTHON

django update field after save

# django update field after save
record = Record.objects.get(id=1)
record.name = "new record name"
record.save(update_fields=['name'])
Comment

PREVIOUS NEXT
Code Example
Python :: how to check a string is empty in python 
Python :: python tkinter button image 
Python :: making ckeditor django responsive 
Python :: permission denied when converting dataframe to csv 
Python :: how to print during multiprocessing 
Python :: python sort 
Python :: how to hide tkinter window 
Python :: isnotin python 
Python :: Disctionary to Array 
Python :: how to get a specific field in django 
Python :: multi threading in python for 2 different functions with return 
Python :: python terminal progress bar 
Python :: logical operators python 
Python :: sort values within groups pandas dataframe 
Python :: create virtual environment python stack overflow 
Python :: python is instance 
Python :: django admin readonly models 
Python :: condition in python 
Python :: python sys 
Python :: pandas create average per group 
Python :: what are test cases in python 
Python :: dataframe look at every second column 
Python :: how to serach for multiple attributes in xpath selenium python 
Python :: stack in python 
Python :: inconsistent use of tabs and spaces in indentation 
Python :: python timestamp to string 
Python :: tuple count in python 
Python :: python s3 
Python :: pygame scroll event 
Python :: bubble sort in python 
ADD CONTENT
Topic
Content
Source link
Name
8+1 =