PYTHON

find all factors of a given number

public List<int> Factor(int number) 
{
    var factors = new List<int>();
    int max = (int)Math.Sqrt(number);  // Round down

    for (int factor = 1; factor <= max; ++factor) // Test from 1 to the square root, or the int below it, inclusive.
    {  
        if (number % factor == 0) 
        {
            factors.Add(factor);
            if (factor != number/factor) // Don't add the square root twice!  Thanks Jon
                factors.Add(number/factor);
        }
    }
    return factors;
}

Find Factors of a Number Using Function

def FindFact(n):
    for i in range(1, n+1):
        if n % i == 0:
            print(i, end=" ")
    print()

print("Enter a Number: ", end="")
try:
    num = int(input())
    print("
Factors of " +str(num)+ " are: ", end="")
    FindFact(num)
except ValueError:
    print("
Invalid Input!")

all factors, factors of a number, factors

from functools import reduce

def factors(n):    
    return set(reduce(list.__add__, 
                ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))