PYTHON

flask return error response

@app.route('/')
def index():
    resp = make_response("Record not found", 400)
    resp.headers['X-Something'] = 'A value'
    return resp

flask error

from flask import Flask, abort
from auth import AuthError
# depending on the error either 400 or any
#just work with the following

@app.errorhandler(404)
def resource_not_found(error):
  return jsonify({
    "success":  True,
    "error": 404,
    "message": "Resource not found"
  }), 404
##This works for any type of status code error
#You'll follow the same steps just change the error value and message :)

### also for Auth error. 

@app.errorhandler(AuthError)
def AuthError(error):
  """Need to return JSON and we'll have to get a response""" 
  response = jsonify(error)
  response.status_code = error.status_code
  
  return response

flask error

from waitress import serve
# app.run(host='0.0.0.0', port=port) # <---- REMOVE THIS
# serve your flask app with waitress, instead of running it directly.
serve(app, host='0.0.0.0', port=port) # <---- ADD THIS