PYTHON

python random phone number

import random

def phn():
    n = '0000000000'
    while '9' in n[3:6] or n[3:6]=='000' or n[6]==n[7]==n[8]==n[9]:
        n = str(random.randint(10**9, 10**10-1))
    return n[:3] + '-' + n[3:6] + '-' + n[6:]

generate random number python

import random

random.randint(lower, upper)

create random phone number python

# import module
import random as r
  
ph_no = []
  
# the first number should be in the range of 6 to 9
ph_no.append(r.randint(6, 9))
  
# the for loop is used to append the other 9 numbers.
# the other 9 numbers can be in the range of 0 to 9.
for i in range(1, 10):
    ph_no.append(r.randint(0, 9))
  
# printing the number
for i in ph_no:
    print(i, end="")

generate random number python

import random
lower_limit = 0 # Can be anything
upper_limit = 100 # Again, can be anything
# Print it out
print(f"Here is a random number: {random.randint(lower_limit, upper_limit)}