PYTHON

python get square root

import math

toSquare = 300
squared = math.sqrt(toSquare)

python square root

import math
a = input("what do you wnat to square root")
print(math.sqrt(a))

how to print the square root of a number in python

from math import * # We import the math module
print(sqrt(16)) # We print the square root of the number 16

how to do a square root in python

a = int(input("enter a real number: "))
sqrt = a**(1/2)
print("the square root of ",a ,"is",sqrt)

square root in python

import math

x = 16
root = math.sqrt(x)

print(root)   // 4

square root python

x = 9
y = x ** 0.5

square root in python

def square_root(num):
  	return num**0.5
#prints out 4
print(square_root(16))
#prints out 10
print(square_root(100))

how to square root in python

import math
answer = math.sqrt(16)

square root python 3

import math
print(math.sqrt(589485))

Get the square root of a number in Python

# How to get the square root of a number in Python:

# First we import the math module
import math

# Then we get the square root of a number using the sqrt() method
print(math.sqrt(9))

# Another way is to do it by doing this calculation: 'number ** 0.5'
print(9 ** 0.5)

how to find a square root of a number using python

import math
whose_square = int(input("Of which number to find square root:- "))
print("The square root of ", whose_square,"is",math.sqrt(whose_square))

How to do square roots in python

# Method 1

from math import sqrt
root = sqrt(25)

# Method 2, more efficient in my opinion*
root = 25 ** (1/2) # If you did not learn this yet in math, by making a fraction to the power of the number, you repeat the multiplication by the numerator but find the root of the denominator in the exponent.

python square root

import numpy
numpy.sqrt(16)  # output: 4.0

python program to find sqaure root of the number

# python program to find the square root of the number
num = int(input("enter a number:"))

num_sqrt = num ** 0.5
print("the sqare root of {0} is {1}".format(num, num_sqrt))