Python

Search

list average python recursion

def average(a):  
    if len(a) == 1:  
        return a[0]  
    else:  
        n = len(a)
        return (a[0] + (n - 1) * average(a[1:])) / n  

print(average([1,2,3]))

Comment

PREVIOUS	NEXT

Code Example
Python :: wpapi
Python :: how to check all possible combinations algorithm python
Python :: create multiple marks python for python
Python :: pixel accuracy image segmentation python
Python :: what does scalar.fit do
Python :: selsearch
Python :: pyxl activate sheet
Python :: gitlab ci deploy key
Python :: corpus.fit(sentences, window=10)
Python :: HTML default value fo radio button input type based on python variable
Python :: Not getting values from Select Fields with jQuery
Python :: win10 python com ports
Python :: find middle permutation of the string in python list
Python :: ax pie rounding
Python :: how to close python in terminal
Python :: ring write the same example using normal for loop the Encrypt() and Decrypt() functions.
Python :: Select right color to threshold and image with opencv
Python :: ring Desktop, WebAssembly and Mobile create an application to ask the user about his/her name.
Python :: search for file in a whole system
Python :: Use of OfficeApi
Python :: python launch ipython from script
Python :: rúllandi veltandi standandi sitjandi
Python :: how to threshold filter geodataframe by column value
Python :: 2checkout ipn validation response python
Python :: python opendatasets
Python :: tensorboard dev upload in background colab
Python :: gizeh python
Python :: np array blurring
Python :: discard method in python
Python :: fill missing values with meadian in df

Search

PYTHON

list average python recursion

ADD CONTENT