PYTHON

python index of max value in list

# any list
a = [1, 7, 3, 12, 5]

# index of minimum element
# if more than 1 minimum, 
# first index is returned
min_index = a.index(min(a))

# index of maximum element
max_index = a.index(max(a))

how to find highest number in list without using max function python

Numbers = [90,78,34,50,100,99]
higest_number = 0
for number in Numbers:
    if number > higest_number:
        higest_number = number

max in a list python

li=[0,70,7,89]
max(li)
#gives the max value 89

find max value in list python

mylist = [1, 7, 3, 12, 5]

min_value = min(mylist)
max_value = max(mylist)

python max from list of list

import numpy as np
datalist = [
    [1, 2, 3, 4, 5, 6],
    [5, 0 ,0, 4, 0, 7],
    [3, 5, 8, 13, 8, 5],
    [5, 6, 7, 3, 4, 5],
    [9, 7, 5, 3, 1, 2]]

a = np.max(datalist)
print(a)
# >> 13

how to find maximum number from python list

num = [1,2,3,4,5]
print(max(num))

find max length of list of list python

temp = [[0,1],[0,2,3], [1], [1,2,3,4]]
print(max(map(len,temp)))
#4

python index max list

number_list = [1, 2, 3]
max_value = max(number_list)
# Return the max value of the list
max_index = number_list.index(max_value)
# Find the index of the max value
print(max_index)

finding the maximum value in a list python

arr = [0, 1, 2, 3]
maximum_value = max(arr)
print(maximum_value) #should print 3

max of a list python

max(list)

find max number in list python

def Max_min(list_of_number):
    largest_number = 0
    for num in list_of_number:
        if num > largest_number:
            largest_number = num
    return largest_number

python max value in list

x = [1, 4, 6]
print(max(x))

find location of max value in python list

>>> m = max(a)
>>> [i for i, j in enumerate(a) if j == m]
[9, 12]

max of a list in python

#!/usr/bin/python

list1, list2 = [123, 'xyz', 'zara', 'abc'], [456, 700, 200]
print "Max value element : ", max(list1)
print "Max value element : ", max(list2)