Python

Search

python beautifulsoup get content of tag

from bs4 import BeautifulSoup

soup = BeautifulSoup(file, "lxml")
content_tag = soup.find("tag", {"class": "tag_class"}).text


""" another option """
from bs4 import BeautifulSoup
import requests

link = requests.get(link)
soup = BeautifulSoup(link, "lxml")
content_tag = soup.findall("a", {"class": "tag_class"}).get("href")

Comment

PREVIOUS	NEXT

Code Example
Python :: flask get ip of user
Python :: how to create a label in tkinter
Python :: charcodeat python
Python :: django connection cursor
Python :: all the positions of a letter occurrences in a string python
Python :: how to import model_to_dict
Python :: python game engine
Python :: pandas convert multiple columns to categorical
Python :: python dataframe remove header
Python :: with urllib.request.urlopen("https://
Python :: tkinter button command with arguments
Python :: python replace all values in a column
Python :: How to find xpath by contained text
Python :: colored text in py
Python :: django iterate over all objects
Python :: Django Check hashed Password
Python :: pandas subtract days from date
Python :: string to list separated by space python
Python :: how to count unique values in a column dataframe in python
Python :: find average of list python
Python :: import django-on-heroku
Python :: pytorch view -1 meaning
Python :: how to create a fixed size empty array in python
Python :: what is python used for
Python :: python copy object
Python :: unable to get local issuer certificate python
Python :: SQLAlchemy query to dict
Python :: pandas difference between dates
Python :: python choose sample from list with replacement
Python :: how to use virtual environment python

Search

PYTHON

python beautifulsoup get content of tag

ADD CONTENT