PYTHON

check if a list contains an item from another list python

## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]

list_B = [2, 3, 6]

check = any(item in list_A for item in list_B)

print(check)
# True

python check if list contains elements of another list

## checking all elements of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3]

check = all(item in list_A for item in list_B)

print(check)
# True

A Python list exists in another list

# Program to check the list contains elements of another list

# List1
List1 = ['python' ,  'javascript', 'csharp', 'go', 'c', 'c++']
 
# List2
List2 = ['csharp1' , 'go', 'python']

check =  all(item in List1 for item in List2)
 
if check is True:
    print("The list {} contains all elements of the list {}".format(List1, List2))    
else :
    print("No, List1 doesn't have all elements of the List2.")

python check list contains another list

>>> items = set([-1, 0, 1, 2])
>>> set([1, 2]).issubset(items)
True
>>> set([1, 3]).issubset(items)
False

python check all elements in list are in another list

check = all ( item in first_list for item in second_list )
# check = True - All elements from first_list are in second_list
# check = False - Not all elements from first_list are not in second_list

check if a list contains any item from another list python

## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]

set_A = set(list_A)
set_B = set(list_B)

print(set_A.intersection(set_B))

# True if there is any element same
# False if there is no element same

check if part of list is in another list python

'''    
    check if list1 contains any elements of list2
'''
result =  any(elem in list1  for elem in list2)
if result:
    print("Yes, list1 contains any elements of list2")    
else :
    print("No, list1 contains any elements of list2")

how to check if a list contains elements in another list

##Taking examples of two python lists.

##Take examples of two lists.

list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]

##the statement for condition is.

check = any(element in list2 for element in list1)

check if a list contains any item from another list python

## using set
list_A = [1, 2, 3, 4]
list_B = [5,1]

set_A = set(list_A)
set_B = set(list_B)

output = False if (set_A.intersection(set_B) == set()) else True
print(output)
# True if there is any element same
# False if there is no element same

Python check if all elements exist in another list

fruits1 = ['Mango','orange','apple','jackfruit']
fruits2 = ['Mango','orange','apple','jackfruit']
new_list=  all(item in fruits1 for item in fruits2)
if new_list is True:
    print("True")    
else :
    print("False")

python check if any elements in a list are different

# Basic syntax:
if your_list.count(your_list[0]) == len(your_list) # or:
if len(set(your_list)) == 1
       
# Example usage 1:
your_list = [1,1,1,1,1,1]
if your_list.count(your_list[0]) == len(your_list):
    print("All elements are identical")
else:
    print("Not all elements are identical")
--> All elements are identical
       
# Example usage 2:
your_list = [1,1,1,2,1,1]
if len(set(your_list)) == 1:
    print("All elements are identical")
else:
    print("Not all elements are identical")
--> Not all elements are identical

Check if list contains any of another list

// You could use a nested Any() for this check which is available on any Enumerable:
bool hasMatch = myStrings.Any(x => parameters.Any(y => y.source == x));

// Faster performing on larger collections would be to project parameters to source and
// then use Intersect which internally uses a HashSet<T> so instead of O(n^2) for the
// first approach (the equivalent of two nested loops) you can do the check in O(n) :
bool hasMatch = parameters.Select(x => x.source)
                          .Intersect(myStrings)
                          .Any();

// source: https://stackoverflow.com/a/11092955

check if one list contains another list element

boolean var = lis1.stream().anyMatch(element -> list2.contains(element));