PYTHON

list to dict python

my_list = ['Nagendra','Babu','Nitesh','Sathya']
my_dict = dict() 
for index,value in enumerate(my_list):
  my_dict[index] = value
print(my_dict)
#OUTPUT
{0: 'Nagendra', 1: 'Babu', 2: 'Nitesh', 3: 'Sathya'}

python convert a list to dict

#python convert a dict to list or a list to dict or a slice a dict or sort a dict by key or value without import
#convert dict to list or list to dict or slice a dict
#1. convert dict to list
temp = [] # not required as [] is mentioned below
s = {'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}#our dict remember
temp = [[k,v]for k,v in s.items()]# temp is now list
print(temp)#[['b', 3], ['a', 2], ['c', 2], ['d', 1], ['e', 1]]

#2. list to dict || pass a list like below
a_dict ={}# not required since we have {} in below
a_dict = {  v[0]:v[1] for k,v in enumerate(temp)}
# OR || a_dict = {  v[0]:v[1] for k,v in enumerate([k,v]for k,v in s.items())}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}

#3. Slice a dict is as simple slice as slicing a list
#see below at temp[0:3] to slice dict to first 4 elements (0 to 3)
a_dict = {  v[0]:v[1] for k,v in enumerate(temp[0:3])}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2}
# OR Also like doing this ([[k,v]for k,v in s.items()][0:3])
#a_dict = { v[0]:v[1] for k,v in enumerate([[k,v]for k,v in s.items()][0:3])}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2}

#Sort a dict #Reverse True for desc and False for asc
#4. Sort a dict by key || s = {'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}
a_dict = dict(sorted(s.items(),key=lambda x:x[0],reverse = False))
print(a_dict )# {'a': 2, 'b': 3, 'c': 2, 'd': 1, 'e': 1}
#Sort a dict by value || put 1 in x:x[1]
a_dict = dict(sorted(s.items(),key=lambda x:x[1],reverse = False))
#{'d': 1, 'e': 1, 'a': 2, 'c': 2, 'b': 3}

#5. Sort dict with import operator
import operator as op#change itemgetter to 0|1 for key|value
a_dict = dict(sorted(s.items(),key=op.itemgetter(0), reverse = False))
print(a_dict)#{'a': 2, 'b': 3, 'c': 2, 'd': 1, 'e': 1}
#refer to #python convert a dict to list or a list to dict or a slice a dict or sort a dict by key or value without import
#convert dict to list or list to dict or slice a dict
#1. convert dict to list
temp = [] # not required as [] is mentioned below
s = {'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}#our dict remember
temp = [[k,v]for k,v in s.items()]# temp is now list
print(temp)#[['b', 3], ['a', 2], ['c', 2], ['d', 1], ['e', 1]]

#2. list to dict || pass a list like below
a_dict ={}# not required since we have {} in below
a_dict = {  v[0]:v[1] for k,v in enumerate(temp)}
# OR || a_dict = {  v[0]:v[1] for k,v in enumerate([k,v]for k,v in s.items())}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}

#3. Slice a dict is as simple slice as slicing a list
#see below at temp[0:3] to slice dict to first 4 elements (0 to 3)
a_dict = {  v[0]:v[1] for k,v in enumerate(temp[0:3])}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2}
# OR Also like doing this ([[k,v]for k,v in s.items()][0:3])
#a_dict = { v[0]:v[1] for k,v in enumerate([[k,v]for k,v in s.items()][0:3])}
print(a_dict)#{'b': 3, 'a': 2, 'c': 2}

#Sort a dict #Reverse True for desc and False for asc
#4. Sort a dict by key || s = {'b': 3, 'a': 2, 'c': 2, 'd': 1, 'e': 1}
a_dict = dict(sorted(s.items(),key=lambda x:x[0],reverse = False))
print(a_dict )# {'a': 2, 'b': 3, 'c': 2, 'd': 1, 'e': 1}
#Sort a dict by value || put 1 in x:x[1]
a_dict = dict(sorted(s.items(),key=lambda x:x[1],reverse = False))
#{'d': 1, 'e': 1, 'a': 2, 'c': 2, 'b': 3}

#5. Sort dict with import operator
import operator as op#change itemgetter to 0|1 for key|value
a_dict = dict(sorted(s.items(),key=op.itemgetter(0), reverse = False))
print(a_dict)#{'a': 2, 'b': 3, 'c': 2, 'd': 1, 'e': 1}
#refer to https://ideone.com/uufYuP
#dn't forget to upvote

python list to dict

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')
out = dict(zip(keys, values))

dictionary to list python

# This is our example dictionary
petAges = {"Cat": 4, "Dog": 2, "Fish": 1, "Parrot": 5}
# This will be our list, epmty for now
petAgesList = []
# Search through the dictionary and find all the keys and values
for key, value in petAges.items(): 
  petAgesList.append([key, value]) # Add the key and value to the list
print(petAgesList) # Print the now-filled list
# Output: [['Cat', 4], ['Dog', 2], ['Fish', 1], ['Parrot', 5]]

python list to dict

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')
out = dict(zip(keys, values))

lists to dictionary python

#This is to convert two lists into a dictionary in Python

#given ListA is key
#given ListB is value

listA = ['itemA','itemB']
listB = ['priceA','priceB']
dict(zip(listA, listB))

# Returns 
{'itemA': 'priceA',
 'itemB': 'priceB'
}

python list to dict

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')
out = dict(zip(keys, values))

python list to dict

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')
out = dict(zip(keys, values))

python list to dict

keys = ('name', 'age', 'food')
values = ('Monty', 42, 'spam')
out = dict(zip(keys, values))

list of dict to dict python

single_dict = dict((k,v) for k,v in [item for subtup in list_of_dict for item in subtup])

list to dictionary

b = dict(zip(a[::2], a[1::2]))

turning list of dicts into dict of lists

#dictionary of lists to list of dictionaries:
v = [dict(zip(DL,t)) for t in zip(*DL.values())]
print(v)
# and back
v = {k: [dic[k] for dic in LD] for k in LD[0]}
print(v)

dict to list python

dict.items()