PYTHON

python string indexof

s = "mouse"
animal_letter = s.find('s')
print animal_letter

find the index of a character in a string python

my_var = 'mummy'. #Find the position of 'm'

#Using find - find returns the index for the first instance from the left.
my_var.find('m')
# Output: 0

#Using rfind - rfind returns the index for the first instance from the right.
my_var.rfind('m')
# Output: 3
# With find() and rfind(), when substring is not found, it returns -1.

#NB: You can use index() and rindex(). In this case, when the substring is not
# found, it raises an exception.

python string indexing

str = 'codegrepper'
# str[start:end:step]
#by default: start = 0, end = len(str), step = 1
print(str[:]) 		#codegrepper
print(str[::]) 		#codegrepper
print(str[5:]) 		#repper
print(str[:8]) 		#codegrep
print(str[::2]) 	#cdgepr
print(str[2:8]) 	#degrep
print(str[2:8:2]) 	#dge
#step < 0 : reverse
print(str[::-1]) 	#reppergedoc
print(str[::-3]) 	#rpgo
# str[start:end:-1]	means start from the end, go backward and stop at start
print(str[8:3:-1]) 	#pperg

python index of string

string = "Hello World"
string_slice = string[1:10] # "ello Worl" (index 1 up to 10)
string_last_chars = string[-5:] # "World" (5th index from last to the end)
H = string[0] # "H"

Python string index

kardiz = "Python"
kardiz[0]

'P'

how to find the indexes of a substring in a string in python

import re
# matches_position_start will be a list of starting index positions
matches_start = re.finditer(word.lower(), string.lower())
matches_position_start = [match.start() for match in matches_start]

# matches_position_end will be a list of ending index positions
matches_end = re.finditer(word.lower(), string.lower())
matches_position_end = [match.end() for match in matches_end]