PYTHON

pop list python

#pop removes the last element
li=[1,2,3,4,5]
li.pop()
#>>>[1, 2, 3, 4]

python list pop

my_list = [-15, 0, 67,45]
print(my_list) # [-15, 0, 67,45]
my_list.pop(3) # 45
print(my_list) # [-15, 0, 67]
#A negative index is an index that is numbered from the back of a list, instead of from the front.For example, the index -1 refers to the last item in a list, while the index -2 refers to the second-last item in a list.The pop() method can be used to delete an item in a list using a negative index.


my_list.pop(-1) # 0
print(my_list) # [-15,0]

python list pop

# Python pop list

some_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # normal python list
print(some_list) # prints [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

some_list.pop() # pop() is used to pop out one index from a list (default index in pop is -1)
print(some_list) # prints [1, 2, 3, 4, 5, 6, 7, 8, 9]

=====================================================
# Output:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[1, 2, 3, 4, 5, 6, 7, 8, 9]

python list pop

# create a list of prime numbers
prime_numbers = [2, 3, 5, 7]

# remove the element at index 2
removed_element = prime_numbers.pop(2)

print('Removed Element:', removed_element)
print('Updated List:', prime_numbers)

# Output: 
# Removed Element: 5
# Updated List: [2, 3, 7]

python list safely pop

In [1]: from typing import List, Any

In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
   ...:     try:
   ...:         return input_list.pop(index)
   ...:     except IndexError:
   ...:         return default_value
   ...:
#								list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)

In [5]: y
Out[5]: 100

# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0