PYTHON

python get file path

import os

def read_file(file_name):
    file_handle = open(file_name)
    print file_handle.read()
    file_handle.close()

file_dir = os.path.dirname(os.path.realpath('__file__'))
print file_dir

#For accessing the file in the same folder
file_name = "same.txt"
read_file(file_name)

#For accessing the file in a folder contained in the current folder
file_name = os.path.join(file_dir, 'Folder1.1/same.txt')
read_file(file_name)

#For accessing the file in the parent folder of the current folder
file_name = os.path.join(file_dir, '../same.txt')
read_file(file_name)

#For accessing the file inside a sibling folder.
file_name = os.path.join(file_dir, '../Folder2/same.txt')
file_name = os.path.abspath(os.path.realpath(file_name))
print file_name
read_file(file_name)

python os get path

import pathlib
pathlib.Path().resolve()

get the path of a module in python

import inspect
inspect.getfile(<mdule name>)

python get file path

import PySimpleGUI as sg
sg.theme("DarkTeal2")
layout = [[sg.T("")], [sg.Text("Choose a file: "), sg.Input(), sg.FileBrowse(key="-IN-")],[sg.Button("Submit")]]

###Building Window
window = sg.Window('My File Browser', layout, size=(600,150))
    
while True:
    event, values = window.read()
    if event == sg.WIN_CLOSED or event=="Exit":
        break
    elif event == "Submit":
        print(values["-IN-"])