PYTHON

Palindrome Check using for loop in python

p = list(input())
for i in range(len(p)):
    if p[i] == p[len(p)-1-i]:
        continue
    else:
         print("NOT PALINDROME")
         break
else:
    print("PALINDROME")

How to check for palindromes in python

def is_palindrome(s):
  reverse = s[::-1]
  if (s == reverse):
    return True
  return False

s1 = 'racecar'
s2 = 'hippopotamus'

print(''racecar' a palindrome -> {}'.format(is_palindrome(s1)))
print(''hippopotamus' a palindrome -> {}'.format(is_palindrome(s2)))


# output

# 'racecar' is a palindrome -> True
# 'hippopotamus' is a palindrome -> False

Python - How To Check if a String Is a Palindrome

word = input() if str(word) == str(word)[::-1] :     print("Palindrome") else:     print("Not Palindrome")

Python Program to Check if binary representation is a palindrome

# Function to check if binary representation of
# a number is palindrome or not
 
def binarypalindrome(num):
 
     # convert number into binary
     binary = bin(num)
 
     # skip first two characters of string
     # because bin function appends '0b' as
     # prefix in binary representation of
     # a number
     binary = binary[2:]
 
     # now reverse binary string and compare
     # it with original
     return binary == binary[-1::-1]
 
# Driver program
if __name__ == "__main__":
    num = 9
    print binarypalindrome(num)

How to check if a given string is a palindrome, in Python?

"""
This implementation checks whether a given
string is a palindrome. A string is 
considered to be a palindrome if it reads the
same forward and backward. For example, "kayak"
is a palindrome, while, "door" is not. 

Let n be the length of the string

Time complexity: O(n), 
Space complexity: O(1)
"""
def isPalindrome(string):
    # Maintain left and right pointers
    leftIdx = 0
    rightIdx = len(string)-1
    while leftIdx < rightIdx:
        # If chars on either end don't match
        # string cannot be a palindrome
        if string[leftIdx] != string[rightIdx]:
            return False
        # Otherwise, proceed to next chars
        leftIdx += 1
        rightIdx -= 1
    return True

print(isPalindrome("kayak"))  # True
print(isPalindrome("door"))  # False

how to check a string is palindrome or not in python

s = "001100"

if s == s[::-1]:
    print(s, "is a Palindrome string.")
else:
    print("Not a palindrome string.")

    

How to check palindrom in python

myString = "aba"
if myString == myString[::-1]:
	print("The string '" + myString + "' is a palindrome")
else:
	print("The string '" + myString + "' is not a palindrome")

check palindrome in python

string = input("Type a string: ")
if string[::-1] == string: 
	print(string,"This string is Palindrome")
else:
	print(string,"This string is not Palindrome")

finding palindrome in python

is_palindrome = lambda phrase: phrase == phrase[::-1]

print(is_palindrome('anna')) # True 
print(is_palindrome('rats live on no evil star')) # True 
print(is_palindrome('kdljfasjf')) # False