PYTHON

get request python

import requests

x = requests.get('https://w3schools.com')
print(x.status_code)

get requests from python

import requests

response = requests.get('<api-endpoint>')
response.raise_for_status()

data = response.json()
print(data)

Python Requests Library Get Method

import requests
 
url = 'https://codegrepper.com/'
response = requests.get(url)
 
print('URL: ', response.url)
print('Status code: ', response.status_code)
print('HTTP header: ', response.headers)

python requests get

# pip install requests
import requests
req = requests.get('<url here>', 'html.parser')
print(req.text)

get requests python

import requests

r = requests.get('https://api.github.com', auth=('user', 'pass'))

print r.status_code
print r.headers['content-type']

python requests get

# requires pip install requests
import requests

# webpage url to sent request to
url = 'https://www.google.com'

# send get requests
x = requests.get(url=url)

# print status code of request
print(x.status_code)

# print webpage source code text
print(x.text)

# print webpage as json
print(x.json)

# print webpage headers
print(x.headers)

# send a get request and timeout if it takes longer than 2.5 seconds
x = requests.get(url=url, timeout=2.5)

# demonstrate how to use the 'params' parameter: query string
x = requests.get(url=url, params={"model": "Mustang"})


####################

# require pip install requests
import requests

url = 'https://www.google.com'
form_data = {'username': 'john', 'password': "pwd"}

# send post request
x = requests.post(url=url, json=form_data)

# send post request and timeout if it takes longer than 3 seconds
x = requests.post(url=url, json=form_data, timeout=3)

# use the 'auth' parameter to send requests with HTTP Basic Auth:
x = requests.post(url, data=from_data, auth=('user', 'pass'))

print(x.text)
print(x.headers)
print(x.status_code)

get requests

app.get('/data', function (req, res) {
  res.send('welcome!');
});