PYTHON

python socket backlog

#Below, you see a python program that acts as a server listening for connection requests to port 9999:

# server.py 
import socket                                         
import time

# create a socket object
serversocket = socket.socket(
            socket.AF_INET, socket.SOCK_STREAM) 

# get local machine name
host = socket.gethostname()                           

port = 9999                                           

# bind to the port
serversocket.bind((host, port))                                  

# queue up to 5 requests
serversocket.listen(5)                                           

while True:
    # establish a connection
    clientsocket,addr = serversocket.accept()      

    print("Got a connection from %s" % str(addr))
    currentTime = time.ctime(time.time()) + "
"
    clientsocket.send(currentTime.encode('ascii'))
    clientsocket.close()
    
    
#The questions is what is the function of the parameter of socket.listen() method (i.e. 5).

#Based on the tutorials around the internet:
#The backlog argument specifies the maximum number of queued connections and should be at least 0; the maximum value is system-dependent (usually 5), the minimum value is forced to 0.