PYTHON

zip python

>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> list(zipped)
[(1, 4), (2, 5), (3, 6)]
>>> x2, y2 = zip(*zip(x, y))
>>> x == list(x2) and y == list(y2)
True

zip python

# zip() Is Build In Function, For Combine Two Values Together
# If The Passed Iterators Have Different Lengths,
# The Iterator With The Least Items Decides The Length Of The New Iterator.

# And Of Course zip() Use With Iterator

# If We Have Tow tuples() Ane We Want Join Together Like :-

# Example :-

a = ("John", "Charles", "Mike")
b = ("Jenny", "Christy", "Monica", "Vicky")

together = zip( a, b )

for names in together :

	print( names ) 

# Will Print ==> ('John', 'Jenny')
#                ('Charles', 'Christy')
#                ('Mike', 'Monica')

print( "-" * 100 ) # Just Separator To Separate Them

# Now I Think You Say Why ( "Vicky" ) Not Print With Them,
# Because The First tuple() Have Just 3 
# If We Want Put ( "Vicky" ) We Need Append 
# Another Value In tuple() /a :-

a = ("John", "Charles", "Mike", "Victor")
b = ("Jenny", "Christy", "Monica", "Vicky")

together = zip( a, b )

for names in together :

	print( names )

# Will Print ('John', 'Jenny')
#            ('Charles', 'Christy')
#            ('Mike', 'Monica')
#            ('Victor', 'Vicky')

# As We See ( "Vicky" ) Has Append, With The New One ==> ( 'Victor' ).

# So The Summary Is, zip() Combine Two Values Together.

# Example With List :-

c = [ "Mido", "Mohamed", "Abdallah" ]
n = [  17, 28, 30  ]

t = zip( c, n )

for mylist in t :

	print( mylist )
    
# Will Print ==> ('Mido', 17)
#                ('Mohamed', 28)
#                ('Abdallah', 30)

python zip()

languages = ['Java', 'Python', 'JavaScript']
versions = [14, 3, 6]

result = zip(languages, versions)
print(list(result))

# Output: [('Java', 14), ('Python', 3), ('JavaScript', 6)]

print(dict(result))

# Output: {'Java': 14, 'Python': 3, 'JavaScript': 6}

python zip function

namelist = ["Avish", "Piyush", "Tom"]
agelist = [17, 22, 38]

for name, age in zip(namelist, agelist):
    print(name, age)

# Avish 17
# Piyush 22
# Tom 38

python zip files

import shutil
shutil.make_archive(output_filename, 'zip', dir_name)

zippython

l1 = [1, 2, 3]
l2 = ['a', 'b', 'c']
list(zip(l1, l2))
#-> [(1, 'a'), (2, 'b'), (3, 'c')]

python zip file

import shutil
import zipfile

# base_name is the name of the zip file you want to create
# format is zip for zip file
# root_dir is the direct path of the folder or file you want to zip
shutil.make_archive(base_name='zip_file_name', format='zip', root_dir='data')

# read zip file from current path
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # create folder name extract_data in current directory with the extracted data
   zip_ref.extractall(path='extract_data')

# Extract a single file from a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_ref:
   # Extract a file name called secrets.dat
   zip_ref.extract(member='secrets.dat')
  
 # extract a list of filename within a zip file
with zipfile.ZipFile(file='zip_file_name.zip', mode='r') as zip_obj:
    # Get list of files names in zip
    filenames = zip_obj.namelist()

    # Iterate over the list of file names in given list & print them
    for filename in filenames:
        print(filename)

python zip

>>> a = [1, 2, 3]
>>> b = [4, 5, 6]
>>> c = zip(a, b)
>>> print(c)
<zip object at 0x7f55cfca3080>
>>> list(c)
[(1, 4), (2, 5), (3, 6)]

python open zip file

with ZipFile('spam.zip') as myzip:
    with myzip.open('eggs.txt') as myfile:
        print(myfile.read())

zip function python

foo = [1, 2, 3]
bar = [4, 5, 6]

parallel_sum = []
for f, b in zip(foo, bar):
    print(f, b)
    parallel_sum.append(f + b) 
    
print(parallel_sum)
# 1	4
# 2	5
# 3	6
# [5, 7, 9]

zip python

>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> for t in zip(x, y):
...   print(t)
...
(1, 4)
(2, 5)
(3, 6)

python zip

"""
Joining any number of iterables by combining elements in order
    - Iterables include: str, list, tuples, dict etc...
    - No error will be incurred if you zip lists of differing lengths,... 
      ...it will simply zip up to the length of the shortest list
"""
lst1 = [1, 2, 3, 4, 5, 7]
lst2 = "mangos"
lst3 = (3.1, 5.4, 0.2, 23.2, 8.88, 898)
lst4 = {"Car": "Mercedes Benz", "Location": "Eiffel Tower", "Organism": "Tardigrade"}
# lst5, lst6, ...

result = list(zip(lst1, lst2, lst3, lst4.keys())) # Check out dictionary methods

print(result)
## [(1, 'm', 3.1, 'Car'), (2, 'a', 5.4, 'Location'), (3, 'n', 0.2, 'Organism')]

zip() python

country = ['United States', 'Canada', 'United Kingdom']
currency = ['USD', 'CAD', 'GBP']
list(zip(country, currency))

#output
#[('United States', 'USD'), ('Canada', 'CAD'), ('United Kingdom', 'GBP')]

zip python

>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> list(zipped)
[(1, 4), (2, 5), (3, 6)]
>>> x2, y2 = zip(*zip(x, y))
>>> x == list(x2) and y == list(y2)
True