PYTHON

re.match python

import re
xx = "guru99,education11 is fun"
r1 = re.findall(r"^w+",xx)
print(r1)

python regex match

# Step-By-Step breakdown:

import re  # We need this module
# First make a regex object containing your regex search pattern. Replace REGEX_GOES_HERE with your regex search. Use either of these:
regex_obj = re.compile(r'REGEX_GOES_HERE', flags=re.IGNORECASE)  # Case-insensitive search:
regex_obj = re.compile(r'REGEX_GOES_HERE')  # Case-sensitive search

# Define the string you want to search inside:
search_txt = "These are oranges and apples and pears"

# Combine the two to find your result/s:
regex_obj.findall(search_txt)

#And it wrapped in print:
print(regex_obj.findall(search_txt))  # Will return a LIST of all matches. Will return empty list on no matches.

re.search with regex python

re.search(pattern, string, flags=0)
# pattern: The first argument is the regular expression pattern we want to search inside the target string.
# string: The second argument is the variable pointing to the target string (In which we want to look for occurrences of the pattern).
# flags: Finally, the third argument is optional and it refers to regex flags by default no flags are applied.

match python

class Point:
    x: int
    y: int

def where_is(point):
    match point:
        case Point(x=0, y=0):
            print("Origin")
        case Point(x=0, y=y):
            print(f"Y={y}")
        case Point(x=x, y=0):
            print(f"X={x}")
        case Point():
            print("Somewhere else")
        case _:
            print("Not a point")

match in python

# import re module
import re
 
Substring ='string'
 
 
String1 ='''We are learning regex with geeksforgeeks
         regex is very useful for string matching.
          It is fast too.'''
String2 ='''string We are learning regex with geeksforgeeks
         regex is very useful for string matching.
          It is fast too.'''
 
# Use of re.search() Method
print(re.search(Substring, String1, re.IGNORECASE))
# Use of re.match() Method
print(re.match(Substring, String1, re.IGNORECASE))
 
# Use of re.search() Method
print(re.search(Substring, String2, re.IGNORECASE))
# Use of re.match() Method
print(re.match(Substring, String2, re.IGNORECASE))

Python match.re and match.string

>>> match.re
re.compile('(d{3}) (d{2})')

>>> match.string
'39801 356, 2102 1111'