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python list remove at index
>>> a = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> del a[-1]
>>> a
[0, 1, 2, 3, 4, 5, 6, 7, 8]
how to remove an element in a list by index python
list = [0, 1, 2, 3, 4, 5]
print(list)
# [0, 1, 2, 3, 4, 5]
del list[0]
print(list)
# [1, 2, 3, 4, 5]
del list[-2]
print(list)
# [1, 2, 3, 5]
del list[0:2]
print(list)
# [3, 5]
remove from list python by index
l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
print(l.pop(0))
# 0
print(l)
# [1, 2, 3, 4, 5, 6, 7, 8, 9]
print(l.pop(3))
# 4
print(l)
# [1, 2, 3, 5, 6, 7, 8, 9]
remove element from list by index
letters = ["a", "b", "c", "d", "e"]
letters.pop(0)
letters.pop(1)
print(letters)
#pop will also return the value if you want to use it
how to remove element from list python by index
>>> l = [1, 2, 43, 3, 4]
>>> l.pop(2) #enter the index as argument
43
>>> l
[1, 2, 3, 4]
python remove by index
a = [0, 1, 2, 3, 4, 5]
el = a.pop(2)
python list remove at index
>>> del a[2:4]
>>> a
[0, 1, 4, 5, 6, 7, 8, 9]
python list remove at index
a = ['a', 'b', 'c', 'd']
a.pop(1)
# now a is ['a', 'c', 'd']
remove from list python by index
print(l.pop())
# 9
print(l)
# [1, 2, 3, 5, 6, 7]
remove from list python by index
print(l.pop(-2))
# 8
print(l)
# [1, 2, 3, 5, 6, 7, 9]
remove from list python by index
l = list(range(10))
print(l)
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
l.clear()
print(l)
# []
remove from list python by index
# print(l.pop(100))
# IndexError: pop index out of range
List Remove At Index
var ls = new List<int>(){1,2,3,4,5};
ls.RemoveAt(2);
// ls elements 1,2,4,5
public void RemoveAt (int index);
Removes the element at the specified index of the List<T>.
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