Python

Search

request.body django

In Python 3.0 to Python 3.5.x, json.loads() will only accept a unicode string, so you must decode request.body (which is a byte string) before passing it to json.loads().

body_unicode = request.body.decode('utf-8')
body = json.loads(body_unicode)
content = body['content']
In Python 3.6, json.loads() accepts bytes or bytearrays. Therefore you shouldn't need to decode request.body (assuming it's encoded in UTF-8, UTF-16 or UTF-32).

Comment

PREVIOUS	NEXT

Code Example
Python :: smtp email template
Python :: tkinter starter code
Python :: python3 hello world
Python :: How do you find the missing number in a given integer array of 1 to 100?
Python :: First Unique Character in a String in python
Python :: accessing data on django sessionstore
Python :: python close browser
Python :: hmac in python
Python :: python dataframe shape
Python :: pandas to_csv no index
Python :: tensorfow list devices
Python :: create a df in pandas
Python :: pandas series to numpy array
Python :: initialize dictionary with empty lists
Python :: print value of tensor
Python :: Learn python 3 the hard way by by Zed Shaw
Python :: generic type python
Python :: last element in list py
Python :: python count total no of word in a text
Python :: how to make a for loop increment by 2 in python
Python :: show image python
Python :: python filter list of strings
Python :: create virtual env
Python :: time now random seed python
Python :: dataframe choose random
Python :: reset django database
Python :: khan academy
Python :: ascii to decimal python
Python :: how to add element at first position in array python
Python :: how to delete a csv file in python

Search

PYTHON

request.body django

ADD CONTENT