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return position of a unique value in python array

def partition(array):
  return {i: (array == i).nonzero()[0] for i in np.unique(array)}

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return position of a unique value in python array

In [304]: array = np.array([1, 1, 2, 3, 2, 1, 2, 3])

In [305]: np.unique(array)            # unique values in `array`
Out[305]: array([1, 2, 3])

In [306]: array == 1                  # retrieve a boolean mask where elements are equal to 1
Out[306]: array([ True,  True, False, False, False,  True, False, False])

In [307]: (array == 1).nonzero()[0]   # get the `True` indices for the operation above
Out[307]: array([0, 1, 5])

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python find indexes of unique elements of a list

import numpy as np
np.unique([1,6,6,2,2,3,4,5,5,5], return_index=True)

>>> (array([1, 2, 3, 4, 5, 6]), array([0, 3, 5, 6, 7, 1], dtype=int64))

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return position of a unique value in python array

return position of a unique value in python array

python find indexes of unique elements of a list

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