PYTHON

how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

dictionary sort python

d={
  3: 4,
  1: 1,
  0: 0,
  4: 3,
  2: 1
}
y=dict(sorted(d.items(), key=lambda item: item[1]))
print(y) # {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

sort dictionary python

l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

python dict order a dict by key

d1 = dict(sorted(d.items(), key = lambda x:x[0]))

sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

python sort dict by key

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}

output:
{-1: 4, 1: 2, 4: -20}

sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

sort dict by value

dict(sorted(x.items(), key=lambda item: item[1]))

sort dict by value python 3

>>> d = {"aa": 3, "bb": 4, "cc": 2, "dd": 1}
>>> for k in sorted(d, key=d.get, reverse=True):
...     k, d[k]
...
('bb', 4)
('aa', 3)
('cc', 2)
('dd', 1)

sort dict by value

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

python dictionary sort

# empty dictionary
dictionary = {}
# lists
list_1 = [1, 2, 3, 4, 5]
list_2 = ["e", "d", "c", "b", "a"]
# populate a dictionary.
for key, value in zip(list_1, list_2):
    dictionary[key] = value
# original
print(f"Original dictionary: {dictionary}")

# Sort dictionary based on value
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda value: value[1]))
print(f"Sort dictionary by value: {dictionary_sorted}")

# Sort dictionary based on key
dictionary_sorted = dict(sorted(dictionary.items(), key=lambda key: key[0]))
print(f"Sort dictionary by key: {dictionary_sorted}")

python sort dict by value

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}

output:
{4: -20, 1: 2, -1: 4}

how to sort dict by value

dict1 = {1: 1, 2: 9, 3: 4}
sorted_dict = {}
sorted_keys = sorted(dict1, key=dict1.get)  # [1, 3, 2]

for w in sorted_keys:
    sorted_dict[w] = dict1[w]

print(sorted_dict) # {1: 1, 3: 4, 2: 9}

python dict sortieren

# dict has no order - use a list to store
l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = list(sorted(l.items(),key=lambda x:x[1],reverse=True))

python sort dict by value

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}

sort dict by values

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

sort a dict by values

{k: v for k, v in sorted(dic.items(), key=lambda item: item[1])}

sort dict of dicts by key

channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'}, 
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'}, 
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'}, 
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'}, 
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'}, 
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'}, 
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}

channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
    print(key, ':', value)

sort dict by value

for w in sorted(d, key=d.get, reverse=True):
    print(w, d[w])

How to sort a Python dict by value

# How to sort a Python dict by value
# (== get a representation sorted by value)

>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1}

>>> sorted(xs.items(), key=lambda x: x[1])
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

# Or:

>>> import operator
>>> sorted(xs.items(), key=operator.itemgetter(1))
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

sort dict by value

d = {'one':1,'three':3,'five':5,'two':2,'four':4}
a = sorted(d.items(), key=lambda x: x[1])    
print(a)

dict sort

[(k,di[k]) for k in sorted(di.keys())] 

sorting dictionary in python

Sorting a dictionary in python