PYTHON

python sort a list of tuples

my_list =[("p",23),("m",2),("q",19),("f",77),("a",50),]
# we will use the 'sort' method
my_list.sort(reverse = True, key = lambda t: t[1])
# the result will be
my_list
[('f', 77), ('a', 50), ('p', 23), ('q', 19), ('m', 2)]

pyhon sort a list of tuples

sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])

sort by tuple

sorted_by_second = sorted(data, key=lambda tup: tup[1])

sort tuple list python

# To have largest first and smalest last
sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1], reverse=True)

how to sort tuples in list python

items =[
    ("product1",10),
    ("product2", 2),
    ("product3", 5)
]

def value(item):     #the function return only the numbers
    return item[1]
  
items.sort(key=value)  #don't call the function but passing it
print(items)


#OR by using Lamda Function

items.sort(key= lambda item: item[1])

# Output >>> [('product2', 2), ('product3', 5), ('product1', 10)]

pyhon sort a list of tuples

# Python program to sort a list of tuples by the second Item 
  
# Function to sort the list of tuples by its second item 
def Sort_Tuple(tup):
    # Getting length of list of tuples
    lst = len(tup)
    for i in range(0, lst):
        for j in range(0, lst-i-1):
            if (tup[j][1] > tup[j + 1][1]):
                temp = tup[j]
                tup[j]= tup[j + 1]
                tup[j + 1]= temp
    return tup