PYTHON

How to check if a list is empty

# For sequences, (strings, lists, tuples), use the fact that empty sequences are false:

# Correct:
if not seq:
if seq:

# Wrong:
if len(seq):
if not len(seq):

Checking if a List Is Empty

my_list = list()

# Check if a list is empty by its length
if len(my_list) == 0: 
  pass # the list is empty

# Check if a list is empty by direct comparison (only works for lists)
if my_list == []: 
  pass # the list is empty

# Check if a list is empty by its type flexibility **preferred method**
if not my_list: 
  pass # the list is empty

# to check if the list is empty use len(l) or not

# to check if the list is empty use len(l) or not 
l = []

if len(l)==0:
  print("list is empty")

#or

if not l:
  print("list is empty") 

how to check list is empty or not

l1 = ["Hire", "the", "top", "1%", "freelancers"]

l2 = []

if l2:
    print("list is not empty")
else:
    print("list is empty")

#Output: "list is empty"

How to check if a list is empty in python

l = []
if len(l) == 0: 
    print("the list is empty")

l = []
if l:
  print("the list is not empty")

else: 
  print("the list is empty")

Check if list is empty in Python Using the len() method

code
# empty list & non-empty list
empty_list = []
non_empty_list = [1, 2, 3, 4]

# check if list is empty
def check_list_empty(lst):
    if len(lst) == 0:
        print('The List is empty')
    else:
        print('The list is not empty')
        
# pass in the lists to check_list_empty
check_list_empty(empty_list)
check_list_empty(non_empty_list)

#Output
The list is empty
The List is not empty