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how to unique list in python

import numpy as np

def unique(list1):
    npArray1 = np.array(list1)
    uniqueNpArray1 = np.unique(npArray1)
    return uniqueNpArray.tolist()
  
list1 = [10, 20, 10, 30, 40, 40]
unique(list1) # [10, 20, 30, 40]
Comment

python list unique in order

>>> items = [1, 2, 0, 1, 3, 2]
>>> list(dict.fromkeys(items))  # Or [*dict.fromkeys(items)] if you prefer
[1, 2, 0, 3]
Comment

count unique elements in list python

from collections import Counter

words = ['a', 'b', 'c', 'a']

Counter(words).keys() # equals to list(set(words))
Counter(words).values() # counts the elements' frequency
Comment

unique list values python ordered

def get_unique(seq):
    seen = set()
    seen_add = seen.add
    return [x for x in seq if not (x in seen or seen_add(x))]
Comment

how to find unique values in list in python

mylist = ['nowplaying', 'PBS', 'PBS', 'nowplaying', 'job', 'debate', 'thenandnow']
myset = set(mylist)
print(myset)
Comment

get unique values from a list

mylist = ['nowplaying', 'PBS', 'PBS', 'nowplaying', 'job', 'debate', 'thenandnow']
myset = set(mylist)
print(myset)
mynewlist = list(myset)
#['nowplaying', 'PBS', 'job', 'debate', 'thenandnow']
Comment

Get unique values from a Python list

# just turn it into a set and then convert again into a list
res = list(set(lst1)))
 
# now check the lengths of the two lists
print(len(res))
print(len(lst1))
Comment

how to find unique sublist in list in python

In [22]: lst = [[1,2,3],[1,2],[1,2,3],[2,3],[4,5],[2,3],[2,4],[4,2]]

In [23]: set(frozenset(item) for item in lst)
Out[23]: 
set([frozenset([2, 4]),
     frozenset([1, 2]),
     frozenset([2, 3]),
     frozenset([1, 2, 3]),
     frozenset([4, 5])])
Comment

how to find unique sublist in list in python

set(tuple(sorted(i)) for i in lst)
Comment

unique list

"""Generation of unique random list of size n
"""
from random import sample
def unique_lst(n):
    return sample(range(10, 100), n) # return a sample of lst (unique lst)
    
# print(unique_lst(10))
Comment

python count unique values in list

len(set(["word1", "word1", "word2", "word3"]))
# set is like a list but it removes duplicates
# len counts the number of things inside the set
Comment

unique items in a list python

list(dict.fromkeys(list_with_duplicates))
Comment

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