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how to unique list in python
import numpy as np
def unique(list1):
npArray1 = np.array(list1)
uniqueNpArray1 = np.unique(npArray1)
return uniqueNpArray.tolist()
list1 = [10, 20, 10, 30, 40, 40]
unique(list1) # [10, 20, 30, 40]
python list unique in order
>>> items = [1, 2, 0, 1, 3, 2]
>>> list(dict.fromkeys(items)) # Or [*dict.fromkeys(items)] if you prefer
[1, 2, 0, 3]
count unique elements in list python
from collections import Counter
words = ['a', 'b', 'c', 'a']
Counter(words).keys() # equals to list(set(words))
Counter(words).values() # counts the elements' frequency
unique list values python ordered
def get_unique(seq):
seen = set()
seen_add = seen.add
return [x for x in seq if not (x in seen or seen_add(x))]
how to find unique values in list in python
mylist = ['nowplaying', 'PBS', 'PBS', 'nowplaying', 'job', 'debate', 'thenandnow']
myset = set(mylist)
print(myset)
get unique values from a list
mylist = ['nowplaying', 'PBS', 'PBS', 'nowplaying', 'job', 'debate', 'thenandnow']
myset = set(mylist)
print(myset)
mynewlist = list(myset)
#['nowplaying', 'PBS', 'job', 'debate', 'thenandnow']
Get unique values from a Python list
# just turn it into a set and then convert again into a list
res = list(set(lst1)))
# now check the lengths of the two lists
print(len(res))
print(len(lst1))
how to find unique sublist in list in python
In [22]: lst = [[1,2,3],[1,2],[1,2,3],[2,3],[4,5],[2,3],[2,4],[4,2]]
In [23]: set(frozenset(item) for item in lst)
Out[23]:
set([frozenset([2, 4]),
frozenset([1, 2]),
frozenset([2, 3]),
frozenset([1, 2, 3]),
frozenset([4, 5])])
how to find unique sublist in list in python
set(tuple(sorted(i)) for i in lst)
unique list
"""Generation of unique random list of size n
"""
from random import sample
def unique_lst(n):
return sample(range(10, 100), n) # return a sample of lst (unique lst)
# print(unique_lst(10))
python count unique values in list
len(set(["word1", "word1", "word2", "word3"]))
# set is like a list but it removes duplicates
# len counts the number of things inside the set
unique items in a list python
list(dict.fromkeys(list_with_duplicates))
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