Search
 
SCRIPT & CODE EXAMPLE
 

SQL

error code 1451 sql

SET FOREIGN_KEY_CHECKS=0;
Now you can fire your query.
DELETE FROM TABLE WHERE ID = 'Somthing';
You can enable foreign key again
SET FOREIGN_KEY_CHECKS=1;
Comment

PREVIOUS NEXT
Code Example
Sql :: script sql backup database sql server 
Sql :: begin transaction sql 
Sql :: sql declare table variable 
Sql :: how to change a collumn name in sql 
Sql :: postgresql update auto_increment value 
Sql :: t sql null or empty string 
Sql :: Mysql Create table with foreign keys. 
Sql :: sqlalchemy.exc.OperationalError: (sqlite3.OperationalError) unable to open database file 
Sql :: show the colums of table sql 
Sql :: join in update query in mysql 
Sql :: sqlite indexes 
Sql :: sql calculate working days between two dates excluding weekends and holidays 
Sql :: sql views 
Sql :: set open file limit mac catalina mysql 
Sql :: mysql select into new table 
Sql :: how to retrive the today date sql 
Sql :: sql find duplicate records in two tables 
Sql :: ValueError: A string literal cannot contain NUL (0x00) characters. 
Sql :: check if value is equal to something sql 
Sql :: How can I tell how many Cores SQL Server is actually using? 
Sql :: how to select distinct in mysql 
Sql :: mysql kill 
Sql :: sql change date format 
Sql :: create database in mysql 
Sql :: postgres duplicate key value violates unique constraint already exists 
Sql :: c# sqldatareader to list 
Sql :: create table in sql server 
Sql :: sort by mysql 
Sql :: change password postgres pgserver 
Sql :: sql insert column 
ADD CONTENT
Topic
Content
Source link
Name
5+2 =