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SQL RIGHT JOIN

SELECT Customers.customer_id, Customers.first_name, Orders.amount
FROM Customers
RIGHT JOIN Orders
ON Customers.customer_id = Orders.customer;
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SQL Syntax of LEFT JOIN

SELECT columns
FROM table1
LEFT JOIN table2
ON table1.column_name = table2.column_name;
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sql right join

SELECT *
FROM table_1
RIGHT JOIN table_2
ON table_1.common_field = table_2.common_field;
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SQL LEFT JOIN

SELECT Customers.customer_id, Customers.first_name, Orders.amount
FROM Customers
LEFT JOIN Orders
ON Customers.customer_id = Orders.customer;
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right join sql

#The RIGHT JOIN keyword Return all rows from the right table (table_name2), even if there are no
#matches in the left table (table_name1). 
syntax->SELECT column_name(s)
FROM table_name1
RIGHT JOIN table_name2
ON table_name1.column_name=table_name2.column_name 
////example////
SELECT Persons.LastName, Persons.FirstName, Orders.OrderNo
FROM Persons
RIGHT JOIN Orders
ON Persons.P_Id=Orders.P_Id
ORDER BY Persons.LastName 
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LEFT JOIN

SELECT
	pka,
	c1,
	pkb,
	c2
FROM
	A
LEFT JOIN B ON pka = fka;
Code language: SQL (Structured Query Language) (sql)
/* https://www.postgresqltutorial.com/postgresql-tutorial/postgresql-left-join/ */
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left join sql

#LEFT JOIN: Return all rows from the left table, even if there are no matches in the right
#table 
syntax->SELECT column_name(s)
FROM table_name1
LEFT JOIN table_name2
ON table_name1.column_name=table_name2.column_name 
////example/////
SELECT Persons.LastName, Persons.FirstName, Orders.OrderNo
FROM Persons
LEFT JOIN Orders
ON Persons.P_Id=Orders.P_Id
ORDER BY Persons.LastName 
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Left join

SELECT *
FROM Table_A A
LEFT JOIN Table_B B
ON A.col = B.col;
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SQL RIGHT JOIN

SELECT Customers.customer_id, Customers.first_name, Orders.amount
FROM Customers
RIGHT JOIN Orders
ON Customers.customer_id = Orders.customer;
Comment

left join

SELECT table1.column1, table2.column2...
FROM table1
RIGHT JOIN table2
ON table1.common_field = table2.common_field;
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left join

Matching part from both table and unmatching part from left table.
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left join

123SELECT columns  FROM table_A  LEFT JOIN table_B ON join_conditionsXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
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left join

You need a first lookup for the values that exist in table1, so make a map using an object:

var maps = {};
for (var i = 0; i < table1.length; i++) {
  maps[table1[i].attr4] = 1;
}

Then you can loop throught the items in table2 and filter them:

var result = [];
for (i = 0; i < table2.length; i++) {
  if (!(table2[i].attr3 in map)) {
    result.push(table2[i]);
  }
}
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left join example sql server

SELECT table1.column1, table2.column2...
FROM table1
LEFT JOIN table2
ON table1.common_field = table2.common_field;
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Left join

SQL> SELECT  ID, NAME, AMOUNT, DATE
   FROM CUSTOMERS
   LEFT JOIN ORDERS
   ON CUSTOMERS.ID = ORDERS.CUSTOMER_ID;
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