TYPESCRIPT

python count number of digits in integer

import math
digits = int(math.log10(n))+1

python count number of digits

num = 3452
count = 0

while num != 0:
    num //= 10
    count += 1

print("Number of digits: " + str(count))

number of digits in a number python

n = 1234 //Any Random Number
digits = len(str(n)) //Saves the number of digits of n into the variable digits

python get digits of number

# x: The int number
# n: Digit index
def digit_extraction_by_index(x, n):
    return (abs(x) // (10 ** n)) % 10

print(digit_extraction_by_index(123, 0)) # 3
print(digit_extraction_by_index(123, 1)) # 2

how to count the number of the digits in an input in python

n=int(input("Enter number:"))
count=0
while(n>0):
    count=count+1
    n=n//10
print("The number of digits in the number are:",count)

count the total number of digits in a number pthon

number = str(input('enter number'))
i = 0
while i in range(len(number)):
    i +=1
print(f'Number of digits: {i}')

how to count digits in python

num = 123456
print(len(str(num)))