TYPESCRIPT

count items in list

>>> from collections import Counter
>>> mylist = ["Bob", "Mike", "Bob", "Mike", "Mike", "Mike", "Bob"]
>>> Counter(mylist)
Counter({'Mike': 4, 'Bob': 3})

count the element in list

from collections import Counter
 
thelist = [1, 4, 2, 3, 5, 4, 5, 6, 7, 8, 1, 3, 4, 5, 9, 10, 11]
c = Counter(thelist)
print(c.most_common(1))

python find the number of elements in a list

list1 = [2,3,4,3,10,3,5,6,3]
elm_count = list1.count(3)
print('The count of element: 3 is ', elm_count)

python count items in list

from collections import Counter
a = [1,2,3,4,5,6,6,6,5,5]
Counter(a)

number of elements list python

>>> mylist = [1,2,3] #list
>>> len(mylist)
3
>>> word = 'hello' # string 
>>> len(word)
5
>>> vals = {'a':1,'b':2} #dictionary
>>> len(vals)
2
>>> tup = (4,5,6) # tuple 
>>> len(tup)
3

number of elements in list in python

# List of strings
listOfElems = ['Hello', 'Ok', 'is', 'Ok', 'test', 'this', 'is', 'a', 'test']
len(s)

check number of elements in list python

>>> len([1,2,3])
3

python number of elements in list of lists

# Basic syntax:
# Using list comprehension:
sum([len(elem) for elem in list_of_lists])

# Example usage:
# Say you want to count the number of elements in a nested list like:
nested_list = [ [1, 2, 3, 45, 6, 7],
                [22, 33, 44, 55],
                [11, 13, 14, 15] ]

sum([len(elem) for elem in nested_list])
--> 14

count number items in list python

mylist = ["abc", "def", "ghi", "jkl", "mno", "pqr"]

print(len(mylist))

# output 6

how to find the amount of numbers in a list on python

>>> someList=[]
>>> print len(someList)
0

Count elements in list Python

List = ["Elephant", "Snake", "Penguin"]

print(len(List))

#	With the 'len' function Python counts the amount of elements 
#	in a list (The length of the list).

count number of element in list

"""Find all occurrences of element in list"""

# If you simply want find how many times an element appears
# use the built-in function count()
def find_occur(lst, item):
	return lst.count(item)

# Test -----------------------------------------------------------
print(find_occur([None, None, 1, 2, 3, 4, 5], None)) # 2

# If you wanna find where they occur instead
# - This returns the indices where element is found within a list

def find(lst, item):
    return [i for (i, x) in enumerate(lst) if x == item]

# Test Code ------------------------------------------------------
from random import randint, choice
lst = [randint(0, 99) for x in range(10)] # random lst
item = choice(lst) # item to find
found = find(lst, item) # lst of where item is found at
print(f"lst: {lst}",
      f"item: {item}",
      f"found: {found}",
      sep = "
")

python number of elements in a list

list_a = ["Hello", 2, 15, "World", 34] #just the array

number_of_elements = len(list_a)

print("Number of elements in the list: ", number_of_elements)

List Count Elements

a = ["more", 4, 6]
print(len(a))
# prints 3

counting the number of items in a list with get in python

counts = {}
names_list = ['John', 'Anne', 'Sam', 'Li', 'Sam', 'John']
for name in names_list:
    counts[name] = counts.get(name,0) +1
print(counts)

python list number of elements

list_a = ["Hello", 2, 15, "World", 34]
number_of_elements = len(list_a)