JAVASCRIPT

parseInt() js

// try using parsInt(x)
// you can then use typeof(x) to confirm 
var myString = "555";
var myInt = parseInt(string);
console.log(typeof myInt); // number

parseint

let str = '24.5'
let numberVariable = parseInt(str, 10)
// numberVariable = 24 (of type Number)

//Format
parseInt(string, base)
// To get the decimal value also (24.5), use parseFloat(string)

parseint js

parseInt(" 0xF", 16);
parseInt(" F", 16);
parseInt("17", 8);
parseInt(021, 8);
parseInt("015", 10);
parseInt(15.99, 10);
parseInt("FXX123", 16);
parseInt("1111", 2);
parseInt("15*3", 10);
parseInt("15e2", 10);
parseInt("15px", 10);
parseInt("12", 13);

//Return: 15

javascript parseint

var myInt = parseInt("12.345");
//myInt = 12

var myFloat = parseFloat("12.345");
//myFloat = 12.345

var myFloat = parseFloat("12.345,50"); //<-- pay attention!
//myFloat = 12.345

var myFloatCrazy = parseFloat(0.1+0.2); //<-- pay MORE attention!
//myFloat = 0.30000000000000004

parseint function javascript

function convertToInterger(mystring) {

	return parseInt(mystring);

}

console.log(convertToInterger("42"));

javascript parseInt() Method

parseInt("-10");
parseInt("-10.33");
parseInt("10");
parseInt("10.33");
parseInt("10 20 30");
parseInt("10 years");
parseInt("years 10");

parseInt() javascript

var myNumber="120";
var myString =parseInt(myNumber); //converts string to number return: 120

use + to parseint in js

const ratingValue = userInput.value;
if(+ratingValue > 1) {}   // + works exactly like a parseInt()

if(parseInt(ratingValue > 1)) {}

Use the parseInt Function

function convertToInteger(str) {
  return parseInt(str);
}

convertToInteger("56");