PYTHON

convert number to binary python

a=10
b=format(a,'b')
print(b)

Output:
  1010
 
a=10
b=format(a,'08b')
print(b)

Output:
  00001010

convert number to binary in python

 bin(6)[2:]  
'110'

# bin() converts to binary, but leaves 0b as the start of the string, remove it

convert integer to binary python

integer = 6
'{0:08b}'.format(integer)
# '00000110'

converting int to binary python

def convert_to_binary(number:int):
    if number == None:
        return "Invalid input"
    elif type(number) == float:
        return "Float is not Handled"
    return format(number, "010b")

print(convert_to_binary(None))
print(convert_to_binary(100))
print(convert_to_binary(6.5))

Python int to binary string

# The int is 37
print("{0:b}".format(37))
# Output - '100101'

python int to binary

bin(1)

python int to binary

n = 24 # this can be any number 
n = bin(n)
n = n[2:]
print(n) 

convert integer to binary in python

format(6, "08b")

how to convert integer to binary string python

binary = bin(7)
print(binary)

python int to binary

print('{0:b}'.format(3))        # '11'
print('{0:8b}'.format(3))       # '      11'
print('{0:08b}'.format(3))      # '00000011'

def int2bin(integer, digits):
    if integer >= 0:
        return bin(integer)[2:].zfill(digits)
    else:
        return bin(2**digits + integer)[2:]
print(int2bin(3, 6))            # '000011'

python int to binary

print(str(1))  # convert number to string
print(int("1"))  # convert string to int
print(float(1))  # convert int to float
print(list('hello'))  # convert string to list
print(tuple('hello'))  # convert string to tuple
print(list((1, 2, 3)))  # convert tuple to list
print(tuple([1, 2, 3]))  # convert list to tuple
print(bool(1))  # convert a number to boolean
print(bool(0))  # convert a number to boolean
print(bool(""))  # convert a string to boolean
print(bool("data"))  # convert string to boolean
print(bin(10))  # convert an integer to a binary string
print(hex(10))  # convert an integer to a hex string
print(oct(10))  # convert an integer to an octal string

Python int to binary

integer = 7
bit_count = 5
print(f'{integer:0{bit_count}b}') # 0 filled

convert integer to binary python

number = 5
print('The binary equivalent of 5 is:', bin(number))

# output - The binary equivalent of 5 is: 0b101
# "0b" indicates that this is a binary number
# 101 is the number (2**2 * 1) + (2**1 * 0) + (2**0 * 1) = 5