from datetime import date
d0 = date(2017, 8, 18)
d1 = date(2017, 10, 26)
delta = d1 - d0
print(delta.days)
from datetime import datetime, timedelta
def date_range(start, end):
delta = end - start # as timedelta
days = [start + timedelta(days=i) for i in range(delta.days + 1)]
return days
start_date = datetime(2008, 8, 1)
end_date = datetime(2008, 8, 3)
print(date_range(start_date, end_date))
from datetime import datetime, date
t1 = date(year = 2018, month = 7, day = 12)
t2 = date(year = 2017, month = 12, day = 23)
t3 = t1 - t2
print("t3 =", t3)
t4 = datetime(year = 2018, month = 7, day = 12, hour = 7, minute = 9, second = 33)
t5 = datetime(year = 2019, month = 6, day = 10, hour = 5, minute = 55, second = 13)
t6 = t4 - t5
print("t6 =", t6)
print("type of t3 =", type(t3))
print("type of t6 =", type(t6))
# Timedelta function demonstration
from datetime import datetime, timedelta
# Using current time
time_for_now = datetime.now()
# printing initial_date
print("initial_date", str(time_for_now))
# Some another datetime
new_final_time = time_for_now +
timedelta(days=2)
# printing new final_date
print("new_final_time", str(new_final_time))
# printing calculated past_dates
print('Time difference:', str(new_final_time - time_for_now))