PYTHON

how to skip next 5 iteration in python

skipcount = -1
song = ['always', 'look', 'on', 'the', 'bright', 'side', 'of', 'life']
for sing in song:
    if sing == 'look' and skipcount <= 0:
        print sing
        skipcount = 3
    elif skipcount > 0:
        skipcount = skipcount - 1
        continue
    elif skipcount == 0:
        print 'a' + sing
        skipcount = skipcount - 1
    else:
        print sing
        skipcoun

skip to next iteration in for loop python

for i in range(1,11):
    if i==5:
        continue
    print (i)

python how to skip iteration

nums = [7,3,-1,8,-9]
positive_nums = []

for num in nums:
    if num < 0: #skips to the next iteration
        continue
    positive_nums.append(num)
        
print(positive_nums) # 7,3,8

skip to next iteration python

# program to display only odd numbers
for num in [20, 11, 9, 66, 4, 89, 44]:
    # Skipping the iteration when number is even
    if num%2 == 0:
        continue
    # This statement will be skipped for all even numbers
    print(num)